Android 阻止短信进入收件箱?
我已经阅读了大部分关于阻止短信进入收件箱的问题。对我来说什么都不管用。所以,我现在有两个应用程序,一个是发送,另一个是接收器。接收方需要检查消息的前四个字符,如果它来自发送方应用程序。然后,阻止它进入收件箱。 他们说我必须提高应用程序的优先级。是的,这是我的舱单Android 阻止短信进入收件箱?,android,Android,我已经阅读了大部分关于阻止短信进入收件箱的问题。对我来说什么都不管用。所以,我现在有两个应用程序,一个是发送,另一个是接收器。接收方需要检查消息的前四个字符,如果它来自发送方应用程序。然后,阻止它进入收件箱。 他们说我必须提高应用程序的优先级。是的,这是我的舱单 <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> <
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<receiver android:name=".SmsReceiver">
<intent-filter android:priority="100">
<action android:name=
"android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>
</application>
<uses-permission android:name="android.permission.READ_SMS"></uses-permission>
<uses-permission android:name="android.permission.SEND_SMS"></uses-permission>
<uses-permission android:name="android.permission.RECEIVE_SMS"></uses-permission>
为了清楚起见,这里是我检查信息的活动
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<receiver android:name=".SmsReceiver">
<intent-filter android:priority="100">
<action android:name=
"android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>
</application>
<uses-permission android:name="android.permission.READ_SMS"></uses-permission>
<uses-permission android:name="android.permission.SEND_SMS"></uses-permission>
<uses-permission android:name="android.permission.RECEIVE_SMS"></uses-permission>
public void onReceive(Context context, Intent intent)
{
//---get the SMS message passed in---
final Bundle bundle = intent.getExtras();
try {
if (bundle != null) {
final Object[] pdusObj = (Object[]) bundle.get("pdus");
for (int i = 0; i < pdusObj.length; i++) {
SmsMessage currentMessage = SmsMessage.createFromPdu((byte[]) pdusObj[i]);
String phoneNumber = currentMessage.getDisplayOriginatingAddress();
String senderNum = phoneNumber;
message = currentMessage.getDisplayMessageBody();
Log.i("SmsReceiver", "senderNum: "+ senderNum + "; message: " + message);
H = currentMessage.getMessageBody();
// Show Alert
int duration = Toast.LENGTH_LONG;
Toast toast = Toast.makeText(context,
"senderNum: "+ senderNum + ", message: " + message, duration);
toast.show();
if(i==0)
H = currentMessage.getMessageBody();
} // end for loop
} // bundle is null
} catch (Exception e) {
Log.e("SmsReceiver", "Exception smsReceiver" +e);
}
check_message = message_checked(H) ;
//---display the new SMS message---
if(check_message)
{
Intent intentHome = new Intent(context,MainActivity.class);
intentHome.putExtra("msgContent", message);
intentHome.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(intentHome);
}
else
System.exit(0);
}
public boolean message_checked(String the_message)
{
String Code = new String("*%#&");
String four_char = "" ;
for(int i = 0 ; i<4 ; i++)
{
four_char += the_message.charAt(i) ;
}
if(four_char.equals(Code))
{
this.abortBroadcast();
return true;
}
else
return false ;
}
public void onReceive(上下文、意图)
{
//---获取传入的SMS消息---
final Bundle=intent.getExtras();
试一试{
if(bundle!=null){
最终对象[]pdusObj=(对象[])bundle.get(“pdus”);
对于(int i=0;i 对于(int i=0;i这是我过去的做法,很抱歉,我的模拟器现在无法工作,因此我无法检查。希望它能有所帮助
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<receiver android:name=".SmsReceiver">
<intent-filter android:priority="100">
<action android:name=
"android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>
</application>
<uses-permission android:name="android.permission.READ_SMS"></uses-permission>
<uses-permission android:name="android.permission.SEND_SMS"></uses-permission>
<uses-permission android:name="android.permission.RECEIVE_SMS"></uses-permission>
public void onReceive(Context context, Intent intent) {
if(intent.getAction().equalsIgnoreCase("android.provider.Telephony.SMS_RECEIVED")){
// Check if the SMS matches our SOS message
SmsMessage[] messages = getMessagesFromIntent(intent);
if(messages != null){
for(int i = 0; i < messages.length; i++){
SmsMessage message = messages[i];
if(matchesMessage(context,message.getDisplayMessageBody())){
Log.i(LOGNAME, "Received Test String! Abort Broadcast");
//put intent call or preferred code here
this.abortBroadcast();
break;
}
}
}
}
}
private boolean matchesMessage(Context context, String message){
SharedPreferences preferences = context.getSharedPreferences(MainSetting.PREFERENCES, Context.MODE_PRIVATE);
String testMessage = preferences.getString(MainSetting.PREFERENCES_TEST, MainSetting.PREFERENCES_STRING_DEFAULT); //this is a string stored in shared preferences
return testMessage.equalsIgnoreCase(message); //ignorecase so that it is not case sensitive
}
private SmsMessage[] getMessagesFromIntent(Intent intent) {
SmsMessage retMsgs[] = null;
Bundle bdl = intent.getExtras();
try {
Object pdus[] = (Object[]) bdl.get("pdus");
retMsgs = new SmsMessage[pdus.length];
for (int n = 0; n < pdus.length; n++) {
byte[] byteData = (byte[]) pdus[n];
retMsgs[n] = SmsMessage.createFromPdu(byteData);
}
} catch (Exception e) {
Log.e(LOGNAME, "fail", e);
}
return retMsgs;
}
public void onReceive(上下文、意图){
if(intent.getAction().equalsIgnoreCase(“android.provider.Telephony.SMS_RECEIVED”)){
//检查SMS是否与我们的SOS消息匹配
SmsMessage[]messages=getMessagesFromIntent(intent);
如果(消息!=null){
for(int i=0;i
}试试这个android:priority=“9999”
是的,我的应用程序在默认收件箱之前收到短信。但我仍然将其放在收件箱中。你想在应用程序读取短信后删除短信吗?是的,这正是我想要的。如果短信不是针对接收者的,就让它放在收件箱中。这正是我做的。不,你把this.abortbroadcast()放在收件箱中;已选中内部公共布尔消息,因此可能“this”指针不再指向onRecieve()?只是一个想法。。。
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<receiver android:name=".SmsReceiver">
<intent-filter android:priority="100">
<action android:name=
"android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>
</application>
<uses-permission android:name="android.permission.READ_SMS"></uses-permission>
<uses-permission android:name="android.permission.SEND_SMS"></uses-permission>
<uses-permission android:name="android.permission.RECEIVE_SMS"></uses-permission>