Android java.net.socketException:协议不支持地址族

Android java.net.socketException:协议不支持地址族,android,web-services,socketexception,Android,Web Services,Socketexception,我创建了一个android应用程序: 这是我的代码: package com.retailer.client; import android.app.Activity; import android.os.Bundle; import org.ksoap2.SoapEnvelope; import org.ksoap2.serialization.SoapObject; import org.ksoap2.serialization.SoapPrimitive; import org

我创建了一个android应用程序: 这是我的代码:

package com.retailer.client;

 import android.app.Activity;
 import android.os.Bundle;
 import org.ksoap2.SoapEnvelope;
  import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.widget.TextView;

public class RetailerActivity extends Activity {
private static final String SOAP_ACTION = "http://ws.retailer.com/customerData";
private static final String METHOD_NAME = "customerData";
private static final String NAMESPACE = "http://ws.retailer.com";
private static final String URL = "http://10.0.0.55:8085/javaws/services/RetailerWS?wsdl";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);  


    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);

    envelope.setOutputSoapObject(request);

    HttpTransportSE ht = new HttpTransportSE(URL);
    try {
        ht.call(SOAP_ACTION, envelope);
        SoapPrimitive response = (SoapPrimitive)envelope.getResponse();


        SoapPrimitive s = response;
        String str = s.toString();
        String resultArr[] = str.split("&");//Result string will split & store in an array

        TextView tv = new TextView(this);

        for(int i = 0; i<resultArr.length;i++){
        tv.append(resultArr[i]+"\n\n");
       }
        setContentView(tv);

    } catch (Exception e) {
        e.printStackTrace();
    }
}
}
package com.retailer.client;
导入android.app.Activity;
导入android.os.Bundle;
导入org.ksoap2.SoapEnvelope;
导入org.ksoap2.serialization.SoapObject;
导入org.ksoap2.serialization.SoapPrimitive;
导入org.ksoap2.serialization.SoapSerializationEnvelope;
导入org.ksoap2.transport.HttpTransportSE;
导入android.widget.TextView;
公共类RetailerActivity扩展了活动{
私有静态最终字符串SOAP_ACTION=”http://ws.retailer.com/customerData";
私有静态最终字符串方法\u NAME=“customerData”;
私有静态最终字符串命名空间=”http://ws.retailer.com";
私有静态最终字符串URL=”http://10.0.0.55:8085/javaws/services/RetailerWS?wsdl";
/**在首次创建活动时调用*/
@凌驾
创建时的公共void(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
SoapObject请求=新的SoapObject(名称空间、方法名称);
SoapSerializationEnvelope=新的SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.setOutputSoapObject(请求);
HttpTransportSE ht=新的HttpTransportSE(URL);
试一试{
ht.呼叫(SOAP_动作、信封);
SoapPrimitive响应=(SoapPrimitive)信封.getResponse();
SOAPs=响应;
字符串str=s.toString();
String resultArr[]=str.split(&);//结果字符串将拆分并存储在数组中
TextView tv=新的TextView(此);

对于(int i=0;i您是否在AndroidManifest.xml中包含权限

<uses-permission android:name="android.permission.INTERNET" />

告诉我朋友们…我如何解决dis错误…请指导我