Android 如何从AbstractSavedStateViewModelFactory动态设置捆绑包

MyViewModelFactory：

class ViewModelFactory @Inject constructor(
    private val viewModelMap: MutableMap<Class<out ViewModel>, ViewModelAssistedFactory<out ViewModel>>,
    owner: SavedStateRegistryOwner,
    defaultArgs: Bundle?
) : AbstractSavedStateViewModelFactory(owner, defaultArgs) {

    @Throws(IllegalStateException::class)
    @Suppress("UNCHECKED_CAST")
    override fun <T : ViewModel?> create(key: String, modelClass: Class<T>, handle: SavedStateHandle): T {
        return viewModelMap[modelClass]?.create(handle) as? T ?: throw IllegalStateException("Unknown ViewModel class")
    }
}

@Inject
lateinit var viewModelFactory: ViewModelFactory
protected val viewModel: ViewModel by lazy { ViewModelProvider(this, viewModelFactory).get(getViewModelClass()) }

@AssistedInject.Factory
interface Factory : ViewModelAssistedFactory<SplashViewModel>

视图模型：

class ViewModelFactory @Inject constructor(
    private val viewModelMap: MutableMap<Class<out ViewModel>, ViewModelAssistedFactory<out ViewModel>>,
    owner: SavedStateRegistryOwner,
    defaultArgs: Bundle?
) : AbstractSavedStateViewModelFactory(owner, defaultArgs) {

    @Throws(IllegalStateException::class)
    @Suppress("UNCHECKED_CAST")
    override fun <T : ViewModel?> create(key: String, modelClass: Class<T>, handle: SavedStateHandle): T {
        return viewModelMap[modelClass]?.create(handle) as? T ?: throw IllegalStateException("Unknown ViewModel class")
    }
}

@Inject
lateinit var viewModelFactory: ViewModelFactory
protected val viewModel: ViewModel by lazy { ViewModelProvider(this, viewModelFactory).get(getViewModelClass()) }

@AssistedInject.Factory
interface Factory : ViewModelAssistedFactory<SplashViewModel>

这样做的目的是可以向ViewModel发送一个参数，比如说一个DetailActivity的ID。 通常我使用“init”方法，但是如果我可以使用

stateholder映射

就更好了。有点像和

---

有道理吗？有可能吗？

我遇到了两种解决方案：

解决方案A:

将ViewModelFactory更改为：

class ViewModelFactory @Inject constructor(
    private val viewModelMap: MutableMap<Class<out ViewModel>, ViewModelAssistedFactory<out ViewModel>>
) {
    fun create(owner: SavedStateRegistryOwner, defaultArgs: Bundle? = null): AbstractSavedStateViewModelFactory {
        return object : AbstractSavedStateViewModelFactory(owner, defaultArgs) {
            @Suppress("UNCHECKED_CAST")
            override fun <T : ViewModel?> create(key: String, modelClass: Class<T>, handle: SavedStateHandle): T {
                return viewModelMap[modelClass]?.create(handle) as? T ?: throw IllegalStateException("Unknown ViewModel class")
            }
        }
    }
}

此外，我们可以将ActivityModule简化为（示例）：

创建我们的

ViewModelAssistedFactory

如下：

class HelloWorldViewModelFactory @Inject constructor(
    private val dependencyA: DependencyA,
    ...
) : ViewModelAssistedFactory<HelloWorldViewModel> {
    override fun create(stateHandle: SavedStateHandle): HelloWorldViewModel {
        return HelloWorldViewModel(stateHandle, dependencyA, ...)
    }
}

---

Elye的这篇文章有助于解决这个问题。

这听起来可能很疯狂，但听起来你需要通过AssistedInject提供

ViewModelProvider.Factory

。我们不应该像对待

ViewModelAssisteFactory

一样尝试

AssistedInject

捆绑包吗？没错。要获取通过

AssistedInject

传入的

捆绑包的
AbstractSavedStateViewModelFactory
实例，您将通过辅助注入创建VMFactory。您能回答这个问题吗
class HelloWorldViewModelFactory @Inject constructor(
    private val dependencyA: DependencyA,
    ...
) : ViewModelAssistedFactory<HelloWorldViewModel> {
    override fun create(stateHandle: SavedStateHandle): HelloWorldViewModel {
        return HelloWorldViewModel(stateHandle, dependencyA, ...)
    }
}

@Inject
lateinit var factory: HelloWorldViewModelFactory
private val viewModel: HelloWorldViewModel by viewModels { ViewModelFactoryAlt(factory, this, intent.extras) }