Android SQLite列错误:表XXX没有名为YYY的列
我查看了以下内容,除其他外,没有发现任何与我的问题相匹配的内容(据我所知): 我收到以下SQLite错误:Android SQLite列错误:表XXX没有名为YYY的列,android,database,sqlite,Android,Database,Sqlite,我查看了以下内容,除其他外,没有发现任何与我的问题相匹配的内容(据我所知): 我收到以下SQLite错误: SQLiteDatabase: Error inserting zipCode=23456 address2= city=state address1=123 petName=qwerty phoneNumber=null vetName=zaw emailAddress= android.
SQLiteDatabase: Error inserting zipCode=23456 address2= city=state address1=123 petName=qwerty phoneNumber=null vetName=zaw emailAddress=
android.database.sqlite.SQLiteException: table vets has no column named petName (code 1): , while compiling: INSERT INTO vets (zipCode,address2,city,address1,petName,phoneNumber,vetName,emailAddress) VALUES (?,?,?,?,?,?,?,?)
我有一种感觉,这和VetTable中的外键有关,但我的研究并没有帮助我理解发生了什么
VetTable的定义如下:
public class VetTable {
public static final String TABLE_VETS = "vets";
public static final String VET_ID = "vetId";
public static final String PET_ID = "petId";
public static final String VET_NAME = "vetName";
public static final String ADDRESS1 = "address1";
public static final String ADDRESS2 = "address2";
public static final String CITY = "city";
public static final String STATE = "state";
public static final String ZIP_CODE = "zipCode";
public static final String PHONE_NUMBER = "phoneNumber";
public static final String EMAIL_ADDRESS = "emailAddress";
public static final String SQL_CREATE =
"CREATE TABLE " + TABLE_VETS + "(" +
VET_ID + " INTEGER PRIMARY KEY UNIQUE, " +
PET_ID + " INTEGER, " +
VET_NAME + " TEXT, " +
ADDRESS1 + " TEXT, " +
ADDRESS2 + " TEXT, " +
CITY + " TEXT, " +
STATE + " TEXT, " +
ZIP_CODE + " TEXT, " +
PHONE_NUMBER + " TEXT, " +
EMAIL_ADDRESS + " TEXT, " +
"FOREIGN KEY(" + PET_ID + ") " +
"REFERENCES pets(petId));";
public static final String SQL_DELETE =
"DROP TABLE" + TABLE_VETS;
}
public void addVetInfo(String name, String address1, String address2, String city, String state, String zip, String phone, String email){
try {
db = this.getWritableDatabase();
values.put(VET_NAME, name);
values.put(ADDRESS1, address1);
values.put(ADDRESS2, address2);
values.put(CITY, city);
values.put(CITY, state);
values.put(ZIP_CODE, zip);
values.put(PHONE_NUMBER, phone);
values.put(EMAIL_ADDRESS, email);
db.insert(TABLE_VETS, null, values);
} catch (SQLException e) {
e.printStackTrace();
}
}
DBHelper代码中的相关代码如下所示:
public class VetTable {
public static final String TABLE_VETS = "vets";
public static final String VET_ID = "vetId";
public static final String PET_ID = "petId";
public static final String VET_NAME = "vetName";
public static final String ADDRESS1 = "address1";
public static final String ADDRESS2 = "address2";
public static final String CITY = "city";
public static final String STATE = "state";
public static final String ZIP_CODE = "zipCode";
public static final String PHONE_NUMBER = "phoneNumber";
public static final String EMAIL_ADDRESS = "emailAddress";
public static final String SQL_CREATE =
"CREATE TABLE " + TABLE_VETS + "(" +
VET_ID + " INTEGER PRIMARY KEY UNIQUE, " +
PET_ID + " INTEGER, " +
VET_NAME + " TEXT, " +
ADDRESS1 + " TEXT, " +
ADDRESS2 + " TEXT, " +
CITY + " TEXT, " +
STATE + " TEXT, " +
ZIP_CODE + " TEXT, " +
PHONE_NUMBER + " TEXT, " +
EMAIL_ADDRESS + " TEXT, " +
"FOREIGN KEY(" + PET_ID + ") " +
"REFERENCES pets(petId));";
public static final String SQL_DELETE =
"DROP TABLE" + TABLE_VETS;
}
public void addVetInfo(String name, String address1, String address2, String city, String state, String zip, String phone, String email){
try {
db = this.getWritableDatabase();
values.put(VET_NAME, name);
values.put(ADDRESS1, address1);
values.put(ADDRESS2, address2);
values.put(CITY, city);
values.put(CITY, state);
values.put(ZIP_CODE, zip);
values.put(PHONE_NUMBER, phone);
values.put(EMAIL_ADDRESS, email);
db.insert(TABLE_VETS, null, values);
} catch (SQLException e) {
e.printStackTrace();
}
}
可以看出,petName既不是VetTable的一部分,也从未包含在VetTable中,也不是addVetInfo中参数列表的一部分。那么,SQLite做了什么使它认为petName应该是VetTable中的一列呢?看起来您的values变量在对象中已经有了该值,请检查以下内容:
public void addVetInfo(String name, String address1, String address2, String city, String state, String zip, String phone, String email){
try {
db = this.getWritableDatabase();
//INITIALIZE YOUR VARIABLE VALUES HERE
ContentValues values = new ContentValues();
//if(name == "Enter vet name") name = null;
values.put(VET_NAME, name);
//if(address1 == "Enter address 1" || address1 == " ") address1 = null;
values.put(ADDRESS1, address1);
//if(address2 == "Enter address 2") address2 = null;
values.put(ADDRESS2, address2);
//if(city == "Enter city") city = null;
values.put(CITY, city);
//if(state == "Enter state") state = null;
values.put(CITY, state);
//if(zip == "Enter zip") zip = null;
values.put(ZIP_CODE, zip);
//if(phone == "Enter phone number") phone = null;
values.put(PHONE_NUMBER, phone);
//if(email == "Enter email address") email = null;
values.put(EMAIL_ADDRESS, email);
db.insert(TABLE_VETS, null, values);
} catch (SQLException e) {
e.printStackTrace();
}
}
对于其他有此SQLite错误问题的人来说,这似乎是因为我的情况下有重复的列名,正如CL在我的帖子中指出的那样。当我纠正这个错误并重新运行代码时,它工作得很好,没有错误
因此,请确保您的列名对于insert语句是正确的。当您尝试将数据插入到不存在列名的表中,或者您尝试插入的架构已使用最新的sequelize.js代码更改时,可能会发生这种情况 可能的问题示例:
- 重命名的列名(例如:以前的
和现在的ID
)UUID
- 新架构设计或完成表架构更改
- 试图将具有错误字段名(例如:
:1234)的数据插入到具有列名(例如:ID
:1234)的表中ID
put(CITY
调用。无论如何,显示的代码不是实际执行的代码。CL,你是什么意思?我没有发布什么代码执行的?CL,谢谢你发现了这两个“CITY”调用!CL,我刚刚将第二个“CITY”更改为“STATE”代码运行正常!但我看不到重复的列名与错误消息之间有任何联系。实际执行的应用程序使用了petName
。此代码没有。因此,您没有实际运行问题中的代码。我发现错误是由我使用重复的“CITY”引起的正如CL的评论所指出的,我无法理解为什么SQLite会说它与“petName”有关。