LoopJ AndroidAsyncHttp库：服务器接收空参数_Android_Android Async Http

LoopJ AndroidAsyncHttp库：服务器接收空参数

android

LoopJ AndroidAsyncHttp库：服务器接收空参数,android,android-async-http,Android,Android Async Http,我在一个Android项目中使用LoopJ AndroidAsyncHttp库，但是当我试图在服务器端获取参数时，我得到了null。我试着使用PHP和Java，得到了同样的结果。我100%确信我的服务器端工作正常，因为我使用了postman chrome插件，它可以工作：客户端代码： public void sendRequest(View v) { try { AsyncHttpClient client = new AsyncHttpClient();

我在一个Android项目中使用LoopJ AndroidAsyncHttp库，但是当我试图在服务器端获取参数时，我得到了null。我试着使用PHP和Java，得到了同样的结果。我100%确信我的服务器端工作正常，因为我使用了postman chrome插件，它可以工作：

客户端代码：

public void sendRequest(View v) {

    try {

        AsyncHttpClient client = new AsyncHttpClient();

        // HashMap<String, String> paramsMap = new HashMap<String,
        // String>();
        // paramsMap.put("action", "Action Value");
        // RequestParams params = new RequestParams(paramsMap);

        RequestParams params = new RequestParams();
        params.add("action", "insert");

        AsyncHttpResponseHandler handler = new AsyncHttpResponseHandler() {

            @Override
            public void onSuccess(int statusCode, Header[] headers,
                    byte[] body) {
                System.out.println("On Success --> Status Code: "
                        + statusCode);
                String response = new String(body);
                System.out.println("On Success --> Response: " + response);
            }

            @Override
            public void onFailure(int statusCode, Header[] headers,
                    byte[] body, Throwable error) {
                System.out.println("On Failure --> Status Code: "
                        + statusCode);
            }
        };

        String url1 = "http://192.168.1.9:8080/Tester";
        String url2 = "http://192.168.1.6/test";
        System.out.println("--->>> Params: " + params.toString());
         client.post(url1, params, handler);


    } catch (Exception e) {
        System.out.println("--> Exception: " + e.getMessage());
    }
}

服务器代码Java:

受保护的无效processRequestHttpServletRequest请求，HttpServletResponse响应抛出ServletException、IOException{

    System.out.println("------->>> " + request.getParameter("action"));
    response.setContentType("text/html;charset=UTF-8");
    try (PrintWriter out = response.getWriter()) {
        /* TODO output your page here. You may use following sample code. */
        out.println("<!DOCTYPE html>");
        out.println("<html>");
        out.println("<head>");
        out.println("<title>Servlet FrontEndController</title>");            
        out.println("</head>");
        out.println("<body>");
        out.println("<h1>Servlet FrontEndController at " + request.getContextPath() + "</h1>");
        out.println("</body>");
        out.println("</html>");
    }
}

您是否尝试过将ProcessRequest更改为doPost…实际上，doPost/doGet都调用ProcessRequest，尽管我使用的是client.post，但只调用了doGet？？？