Android HttpConnectionUrl始终返回状态代码307

我正在尝试访问一个web服务。它在安卓4.4或安卓5.X上运行良好。但当我试图点击“

http://inmotion-prod.cloudapp.net:145/service1.svc/json/GetCustomerUUID“

使用android 4.1.1，它总是返回307状态码。但这个url在android 4.4或5.x上运行良好。我还试着点击其他url，它在安卓4.1.1上运行良好。 那么请告诉我问题出在哪里

Log.i(TAG, url);
        String response = null;
        HttpURLConnection conn = null;
        try {
            URL webServiceUrl = new URL(url);
            conn = (HttpURLConnection) webServiceUrl
                    .openConnection();
            Log.i(TAG, "Connection open");
            conn.setRequestMethod(GET);
            conn.setConnectTimeout(CONNECTION_TIME_OUT);
            conn.setRequestProperty(CONTENT_TYPE, contentType);
            conn.setRequestProperty(ACCEPT_TYPE, acceptType);
            conn.setDoInput(true);
            conn.connect();
            Log.i(TAG, "Connection Connected");

            if (conn.getResponseCode() == HttpURLConnection.HTTP_OK && conn.getInputStream() != null) {
                response = StreamUtility.convertStreamToString(conn.getInputStream());
                conn.getInputStream().close();
            }

        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            if (conn != null) {
                conn.disconnect();
            }
        }

        return response;
    }

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将您的URL地址替换为

http://inmotion-prod.cloudapp.net:145/service1.svc/json/GetCustomerUUID/

（注意结尾处的

/

）。响应代码将为

200

---

更新：

使用您当前的URL地址（

http://inmotion-prod.cloudapp.net:145/service1.svc/json/GetCustomerUUID

）如果最后没有

/

，您可以使用以下代码：

String address = "http://inmotion-prod.cloudapp.net:145/service1.svc/json/GetCustomerUUID";
URL url = new URL(address);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setInstanceFollowRedirects(false);
// if print out (debug or logging), you will see secondURL has / at the end
URL secondURL = new URL(urlConnection.getHeaderField("Location"));
HttpURLConnection urlConnection1 = (HttpURLConnection) secondURL.openConnection();

然后使用

urlConnection1.getResponseCode（）

---

希望有帮助

BNK的回答很有帮助，我这样修复了它，这样它也可以在较新的设备上工作（location header返回为null/empty！）

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发生这种情况的原因是头在此处检查代码：-conn.setRequestProperty（令牌，头）；确保无论传递给API clienti中确认的webservices的是什么，如果我没有传递任何头文件，那么“conn”的所有设置操作都将被视为头文件。首先，在RESTAPI客户端检查您的Web服务，然后实现代码。这是一个非常恼人的行为（bug？）。谢谢你的代码。效果很好

String headerLocation = httpsUrlConnection.getHeaderField("Location");
logger.debug("Location header: " + headerLocation);

// if the redirect URL ends with a "/" sign, but the original URL does not, it's probably the redirect bug
String originalURL = url.toString();
if (!TextUtils.isEmpty(headerLocation) && headerLocation.endsWith("/") && !originalURL.endsWith("/"))
    {
    logger.info("Redirect Location differs from original URL, create new connection to: " + headerLocation);
    httpsUrlConnection = (HttpsURLConnection) new URL(headerLocation).openConnection();

    // optional
    httpsUrlConnection.setSSLSocketFactory(sslSocketFactory);
    }