Android 从活动更新片段中的textView

Android 从活动更新片段中的textView,android,Android,我在片段中有3个文本视图 在MainActivity中,我有一个每10秒生成3个字符串的方法 现在我想从活动中更新文本视图,但我不知道如何更新 有人能给我一些建议吗?为xml文件中的文本视图设置id:android:id=“@+id/myId 然后这样做: TextView textView = (TextView) findViewById(R.id.myId); textView.setText("updated text"); 设置xml文件中文本视图的id:android:id=“@+

我在片段中有3个文本视图

在MainActivity中,我有一个每10秒生成3个字符串的方法

现在我想从活动中更新文本视图,但我不知道如何更新


有人能给我一些建议吗?

为xml文件中的文本视图设置id:
android:id=“@+id/myId
然后这样做:

TextView textView = (TextView) findViewById(R.id.myId);
textView.setText("updated text");

设置xml文件中文本视图的id:
android:id=“@+id/myId
然后这样做:

TextView textView = (TextView) findViewById(R.id.myId);
textView.setText("updated text");

它可以通过在活动中使用接口来实现,并在生成字符串时将该参数传递给片段:

public class MainActivity extends AppCompatActivity {
private OnGenerateStringListener onGenerateStringListener;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    onGenerateStringListener = (OnGenerateStringListener) this;

    onStartGenerateStringFragment();

    try {
        generateString();
    } catch (InterruptedException e) {
        e.printStackTrace();
    }

}

private void generateString() throws InterruptedException {

    // After string a is generated
    String a = "test one";
    onGenerateStringListener.onGeneratedString(a);

    // Sleep 10 secs
    Thread.sleep(10000);

    String b = "test Two";
    onGenerateStringListener.onGeneratedString(b);

    // Sleep 10 secs
    Thread.sleep(10000);

    String c = "test Three";
    onGenerateStringListener.onGeneratedString(c);

}

private void onStartGenerateStringFragment() {
 //Method to launch your fragment
}    

interface OnGenerateStringListener {
    void onGeneratedString(String string);
}

}
这是你的
片段
课程:

public class FragmentTextView extends Fragment implements MainActivity.OnGenerateStringListener{

    private View view;
    private TextView textViewOne;
    private TextView textViewTwo;
    private TextView textViewThree;

    @Nullable
    @Override
    public View onCreateView(@NonNull LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
        if (view != null) {
            ViewGroup group = (ViewGroup) view.getParent();
            if (group != null) {
                group.removeView(view);
            }
        } else {
            view = inflater.inflate(R.layout.fragment_layout, container, false);
            textViewOne = view.findViewById(R.id.textViewOne);
            textViewTwo = view.findViewById(R.id.textViewTwo);
            textViewThree = view.findViewById(R.id.textViewThree);
        }
        return view;
    }


    @Override
    public void onGeneratedString(String string) {
        switch (string) {
            // Use a switch case to determine which text view gets what parameters
            // for the sake of the example, I just passed a dummy text view input
            case "test one":
                textViewOne.setText(string);
                break;
            case "test Two":
                textViewTwo.setText(string);
                break;
            case "test Three":
                textViewThree.setText(string);
                break;
        }
    }
}

它可以通过在活动中使用接口来实现,并在生成字符串时将该参数传递给片段:

public class MainActivity extends AppCompatActivity {
private OnGenerateStringListener onGenerateStringListener;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    onGenerateStringListener = (OnGenerateStringListener) this;

    onStartGenerateStringFragment();

    try {
        generateString();
    } catch (InterruptedException e) {
        e.printStackTrace();
    }

}

private void generateString() throws InterruptedException {

    // After string a is generated
    String a = "test one";
    onGenerateStringListener.onGeneratedString(a);

    // Sleep 10 secs
    Thread.sleep(10000);

    String b = "test Two";
    onGenerateStringListener.onGeneratedString(b);

    // Sleep 10 secs
    Thread.sleep(10000);

    String c = "test Three";
    onGenerateStringListener.onGeneratedString(c);

}

private void onStartGenerateStringFragment() {
 //Method to launch your fragment
}    

interface OnGenerateStringListener {
    void onGeneratedString(String string);
}

}
这是你的
片段
课程:

public class FragmentTextView extends Fragment implements MainActivity.OnGenerateStringListener{

    private View view;
    private TextView textViewOne;
    private TextView textViewTwo;
    private TextView textViewThree;

    @Nullable
    @Override
    public View onCreateView(@NonNull LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
        if (view != null) {
            ViewGroup group = (ViewGroup) view.getParent();
            if (group != null) {
                group.removeView(view);
            }
        } else {
            view = inflater.inflate(R.layout.fragment_layout, container, false);
            textViewOne = view.findViewById(R.id.textViewOne);
            textViewTwo = view.findViewById(R.id.textViewTwo);
            textViewThree = view.findViewById(R.id.textViewThree);
        }
        return view;
    }


    @Override
    public void onGeneratedString(String string) {
        switch (string) {
            // Use a switch case to determine which text view gets what parameters
            // for the sake of the example, I just passed a dummy text view input
            case "test one":
                textViewOne.setText(string);
                break;
            case "test Two":
                textViewTwo.setText(string);
                break;
            case "test Three":
                textViewThree.setText(string);
                break;
        }
    }
}

你为什么不让片段处理这个功能呢?是的,我只是觉得他在问如何更改TextView中的文本如果我尝试在活动中从片段中找到findviewbyid,我得到Null我相信转换到(TextView)现在是多余的是,我写这篇文章是因为我不确定他们有什么版本的Android Studio,为什么你不让fragments来处理这个功能?是的,我想他是在问如何更改TextView中的文本如果我尝试在活动中从fragments中找到findviewbyid,我得到Null我相信casting to(TextView)现在是多余的了是的,我写这篇文章是因为我不确定他们有什么版本的Android Studio