Android ExpandableListAdapter中子级的上下文菜单

如果用户长时间单击

ExpandableListAdater

的项目（组或组子项），我试图创建一个

ContextMenu

，但是

ContextMenu

仅显示长时间单击组项，而不显示组子项：

一旦创建：

@Override
protected void onCreate(Bundle savedInstanceState) {
    //...
    setListAdapter(mAdapter);
    registerForContextMenu(getExpandableListView());

onCreateContextMenu：

@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);
    Log.i("", "Click");
    ExpandableListView.ExpandableListContextMenuInfo info = (ExpandableListView.ExpandableListContextMenuInfo) menuInfo;

    int type = ExpandableListView.getPackedPositionType(info.packedPosition);
    int groupPosition = ExpandableListView.getPackedPositionGroup(info.packedPosition);
    int childPosition = ExpandableListView.getPackedPositionChild(info.packedPosition);

    // Show context menu for groups
    if (type == ExpandableListView.PACKED_POSITION_TYPE_GROUP) {
        menu.setHeaderTitle("Group");
        menu.add(0, 0, 1, "Delete");

        // Show context menu for children
    } else if (type == ExpandableListView.PACKED_POSITION_TYPE_CHILD) {
        menu.setHeaderTitle("Child");
        menu.add(0, 0, 1, "Delete");
    }
}

onContextItemSelected：

@Override
public boolean onContextItemSelected(MenuItem item) {
    ExpandableListView.ExpandableListContextMenuInfo info = (ExpandableListView.ExpandableListContextMenuInfo) item
            .getMenuInfo();

    int type = ExpandableListView.getPackedPositionType(info.packedPosition);
    int groupPosition = ExpandableListView.getPackedPositionGroup(info.packedPosition);
    int childPosition = ExpandableListView.getPackedPositionChild(info.packedPosition);

    if (type == ExpandableListView.PACKED_POSITION_TYPE_GROUP) {
        // do something with parent

    } else if (type == ExpandableListView.PACKED_POSITION_TYPE_CHILD) {
        // do someting with child
    }

    return super.onContextItemSelected(item);
}

我想我错过了一些东西，因为如果我长时间点击一个孩子，“点击”不会被记录。我认为如果我长时间单击一个孩子，就不会调用

onCreateContextMenu

。如何为

ExpandableListAdapter

组子级显示

ContextMenu

@Override
public boolean isChildSelectable(int groupPosition, int childPosition) {
    // Check your child items here
    return true;
}

自动实现为

返回false