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Android Kotlin-从网络提供商处获取位置时出现问题_Android_Kotlin_Gps_Location_Android Gps - Fatal编程技术网

Android Kotlin-从网络提供商处获取位置时出现问题

Android Kotlin-从网络提供商处获取位置时出现问题,android,kotlin,gps,location,android-gps,Android,Kotlin,Gps,Location,Android Gps,我必须在Android应用程序中从用户设备获取位置 我做了如下工作: 首先,我已检查运行时位置权限。拍摄成功 秒,检查GPS是否启用,如果GPS提供商工作正常,我可以从GPS提供商获取纬度和经度 第三个,如果GPS关闭,我将尝试从网络提供商处获取位置。 但是,在这种情况下,有时我无法成功获取位置 所以,我必须让用户打开GPS,并在打开GPS后获得位置 我很困惑,因为许多演示提供了打开GPS的意图。 如何动态打开GPS? 如何通知用户已打开GPS 谢谢。这是Gradle插件,就我而言,它的版本是:

我必须在Android应用程序中从用户设备获取位置

我做了如下工作:

首先,我已检查运行时位置权限。拍摄成功

,检查GPS是否启用,如果GPS提供商工作正常,我可以从GPS提供商获取纬度和经度

第三个,如果GPS关闭,我将尝试从网络提供商处获取位置。 但是,在这种情况下,有时我无法成功获取位置

所以,我必须让用户打开GPS,并在打开GPS后获得位置

我很困惑,因为许多演示提供了打开GPS的意图。 如何动态打开GPS? 如何通知用户已打开GPS


谢谢。

这是Gradle插件,就我而言,它的版本是:“17.0.0”

implementation "com.google.android.gms:play-services-location:$parent.ext.playServicesVersion"
这是
GpsUtils

import android.annotation.SuppressLint;
import android.app.Activity;
import android.content.Context;
import android.content.IntentSender;
import android.location.LocationManager;
import android.util.Log;
import android.widget.Toast;

import androidx.annotation.NonNull;

import com.google.android.gms.common.api.ApiException;
import com.google.android.gms.common.api.ResolvableApiException;
import com.google.android.gms.location.LocationRequest;
import com.google.android.gms.location.LocationServices;
import com.google.android.gms.location.LocationSettingsRequest;
import com.google.android.gms.location.LocationSettingsResponse;
import com.google.android.gms.location.LocationSettingsStatusCodes;
import com.google.android.gms.location.SettingsClient;
import com.google.android.gms.tasks.OnFailureListener;
import com.google.android.gms.tasks.OnSuccessListener;

public class GpsUtils {

    private Context context;
    private SettingsClient mSettingsClient;
    private LocationSettingsRequest mLocationSettingsRequest;
    private LocationManager locationManager;
    private static final String TAG = GpsUtils.class.getSimpleName();

    public GpsUtils(Context context) {

        this.context = context;
        locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
        mSettingsClient = LocationServices.getSettingsClient(context);

        LocationRequest locationRequest = LocationRequest.create();
        locationRequest.setPriority(LocationRequest.PRIORITY_HIGH_ACCURACY);
        locationRequest.setInterval(2 * 1000);
        locationRequest.setFastestInterval(2 * 1000);
        LocationSettingsRequest.Builder builder = new LocationSettingsRequest.Builder()
                .addLocationRequest(locationRequest);
        mLocationSettingsRequest = builder.build();

        //**************************
        builder.setAlwaysShow(true); //this is the key ingredient
        //**************************
    }

    // method for turn on GPS
    public void turnGPSOn(onGpsListener onGpsListener) {

        if (locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER)) {
            if (onGpsListener != null) {
                onGpsListener.gpsStatus(true);
            }
        } else {
            mSettingsClient
                    .checkLocationSettings(mLocationSettingsRequest)
                    .addOnSuccessListener((Activity) context, new OnSuccessListener<LocationSettingsResponse>() {
                        @SuppressLint("MissingPermission")
                        @Override
                        public void onSuccess(LocationSettingsResponse locationSettingsResponse) {

                            //  GPS is already enable, callback GPS status through listener
                            if (onGpsListener != null) {
                                onGpsListener.gpsStatus(true);
                            }
                        }
                    })
                    .addOnFailureListener((Activity) context, new OnFailureListener() {
                        @Override
                        public void onFailure(@NonNull Exception e) {
                            int statusCode = ((ApiException) e).getStatusCode();
                            switch (statusCode) {
                                case LocationSettingsStatusCodes.RESOLUTION_REQUIRED:

                                    try {
                                        ResolvableApiException rae = (ResolvableApiException) e;
                                        rae.startResolutionForResult((Activity) context, Appconstants.GPS_REQUEST);
                                    } catch (IntentSender.SendIntentException sie) {
                                        Log.i(TAG, "PendingIntent unable to execute request.");
                                    }
                                    break;
                                case LocationSettingsStatusCodes.SETTINGS_CHANGE_UNAVAILABLE:
                                    String errorMessage = "Location settings are inadequate, and cannot be " +
                                        "fixed here. Fix in Settings.";

                                    Toast.makeText((Activity) context, errorMessage, Toast.LENGTH_LONG).show();
                            }
                        }
                    });
        }
    }

    public interface onGpsListener {
        void gpsStatus(boolean isGPSEnable);
    }
}

您可以从中阅读有关
设置客户端的更多信息。

您好,先生,我找到了显示GPS对话框的方法。现在,问题是如何通知用户现在是否按下了OK键?如果他们按下
OK
,最终您将启用GPS,反之亦然,对吗?点击“是”或“否”Btn,您希望实现什么?总之,
addOnSuccessListener
addOnFailureListener
可以帮助您吗?
  GpsUtils(this).turnGPSOn { isGPSEnable ->
                isGPS = isGPSEnable  // You can get the callback here..
            }