Android 迭代从多维数组转换的JSON数据

Android 迭代从多维数组转换的JSON数据,android,arrays,json,multidimensional-array,apache-httpclient-4.x,Android,Arrays,Json,Multidimensional Array,Apache Httpclient 4.x,这很好用 我使用此代码块读取从FetchData.php文件获取的json数据;我的代码如下所示: HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://10.0.2.2/mydummyproject/FetchData.php"); TextView textView = (TextView)findViewById(R.id.textView1); try {

这很好用

我使用此代码块读取从
FetchData.php
文件获取的json数据;我的代码如下所示:

HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://10.0.2.2/mydummyproject/FetchData.php");
TextView textView = (TextView)findViewById(R.id.textView1);
try {

    HttpResponse response = httpclient.execute(httppost);
    String jsonResult = inputStreamToString(response.getEntity().getContent()).toString();
    JSONObject object = new JSONObject(jsonResult);

    String name = object.getString("name");
    String verion = object.getString("version");
    textView.setText(name + " - " + verion);

} 
catch (JSONException e) {
    e.printStackTrace();
}
//Loop over each json object

for data in JSONObject:

    // Print name and version
    textView.setText(data.name + " - " + data.version)
来自我的PHP文件的数据
FetchData.PHP

{"name":"John Doe","version":"Android 4.4"}
[{"name":"John Doe","version":"Android 4.4"}, {"name":"Seliana Gomez","version":"Android 4.1"}, {"name":"Nerdy Trumph","version":"Android 4.4"}]
问题

我还有另一种类型的数据来自
FetchDataTwo.php

{"name":"John Doe","version":"Android 4.4"}
[{"name":"John Doe","version":"Android 4.4"}, {"name":"Seliana Gomez","version":"Android 4.1"}, {"name":"Nerdy Trumph","version":"Android 4.4"}]
现在,上面的一个也是我通过在
PHP
文件中执行
json\u encode($多维数组)
得到的json数据

问题

如何从json循环这个多维编码数组。所以我可以这样迭代(json数据对json数据):

[注意:下面是我需要获取的数据,我不想以显示的方式排列。这只是为了清晰和举例]

Name | Version John Doe | Android 4.4 Seliana Gomez | Android 4.1 Nerdy Trumph | Android 4.4
看起来您所要做的就是迭代
JSONArray

try {
    JSONArray array =  new JSONArray(inputString);
    for (int i = 0; i < array.length(); i++) {
        JSONObject jsonObject = array.optJSONObject(i);
        // Json Object handling...
    }
} catch (JSONException e) {
    // handle
}
然后使用
Gson
实例自动解析字符串

Gson gson = new Gson();
NameVersionPair[] result = gson.fromJson(inputString, NameVersionPair[].class);