Android 尝试使用电话类获取单元格位置时发生ClassCastExeption错误
我从同一个用户那里收到了一些关于Google Play的关于CdmaCellLocation的报告：Android 尝试使用电话类获取单元格位置时发生ClassCastExeption错误,android,location,telephony,Android,Location,Telephony,我从同一个用户那里收到了一些关于Google Play的关于CdmaCellLocation的报告： java.lang.ClassCastException: android.telephony.cdma.CdmaCellLocation 这是一项使用Cell Network报告用户位置的服务，请注意，它100%适用于我，我没有关于此错误的任何其他报告，以下是onStart的代码： public class ServiceLocation extends Service{ int my
java.lang.ClassCastException: android.telephony.cdma.CdmaCellLocation
public class ServiceLocation extends Service{
int myLatitude , myLongitude;
private String str2;
static SharedPreferences prefs;
private String numtosend;
public int onStartCommand(Intent itn,int num1, int num2){
prefs = getSharedPreferences("Preferences",
Context.MODE_PRIVATE);
if(isAirplaneModeOn(this)){
stopSelf();
}
Bundle extras = itn.getExtras();
if(extras.containsKey("ExtraName") != true){
str2 = itn.getStringExtra("Number");
}
location(str2);
return 0;
}
public void location(String num){
// TODO Auto-generated method stub
TelephonyManager telephonyManager = (TelephonyManager)getSystemService(Context.TELEPHONY_SERVICE);
if(telephonyManager.getSimState() != TelephonyManager.SIM_STATE_ABSENT){
numtosend = "Phone Number (If Avaible) : " + " " + telephonyManager.getLine1Number() + " " + " Sim Serial : " + telephonyManager.getSimSerialNumber() + " " + "IMEI : " + telephonyManager.getDeviceId();
}
else {
numtosend = this.getResources().getString(R.string.txtNoSimCard) + telephonyManager.getDeviceId();
}
GsmCellLocation cellLocation = (GsmCellLocation) telephonyManager.getCellLocation();
int cid = cellLocation.getCid();
int lac = cellLocation.getLac();
if(RqsLocation(cid, lac)){
if(str2.equals("") != true && str2.equals(null) != true) {
SmsManager.getDefault().sendTextMessage(num, null, this.getResources().getString(R.string.txtGPSPosition) + "(40-250 Meters Accuracy) : "+"http://maps.google.com/?q="+String.valueOf((float)myLatitude/1000000) +","+String.valueOf((float)myLongitude/1000000), null, null);
}
if(gmailaccount.equals("") != true && gmailpass.equals(null) != true){
P m = new P(gmailaccount , gmailpass);
String[] Mail = {mail};
m.setTo(Mail);
m.setFrom("AnonymousMail@gmail.com");
m.setSubject("Location");
m.setBody(this.getResources().getString(R.string.txtGPSPosition) + "(~300 Meters Accuracy) : " + "http://maps.google.com/?q="+String.valueOf((float)myLatitude/1000000) +","+String.valueOf((float)myLongitude/1000000) + " " + str2 + " " + numtosend);
try {
if(m.send()){
stopSelf();
}
else {
if(str2.equals("") != true) {
SmsManager.getDefault().sendTextMessage(str2, null, "Impossible to Send a Message to your Emergency Mail Address !", null, null);
}
stopSelf();
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
else{
if(str2.equals("") != true && str2.equals(null) != true) {
SmsManager.getDefault().sendTextMessage(num, null, this.getResources().getString(R.string.txtInternetOffLocation), null, null);
}
if(gmailaccount.equals("") != true && gmailpass.equals(null) != true){
P m = new P(gmailaccount , gmailpass);
String[] Mail = {mail};
m.setTo(Mail);
m.setFrom("AnonymousMail@gmail.com");
m.setSubject("Location");
m.setBody(this.getResources().getString("Internet Off));
try {
if(m.send()){
stopSelf();
}
else {
if(str2.equals("") != true) {
}
stopSelf();
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
stopSelf();
}
java.lang.RuntimeException: Unable to start service com.xxx.xxx.xxx.ServiceLocation@4051b930 with Intent { cmp=com.xxx.xxx.xxx/.ServiceLocation (has extras) }: java.lang.ClassCastException: android.telephony.cdma.CdmaCellLocation
at android.app.ActivityThread.handleServiceArgs(ActivityThread.java:2052)
at android.app.ActivityThread.access$2800(ActivityThread.java:117)
at android.app.ActivityThread$H.handleMessage(ActivityThread.java:994)
at android.os.Handler.dispatchMessage(Handler.java:99)
at android.os.Looper.loop(Looper.java:130)
at android.app.ActivityThread.main(ActivityThread.java:3683)
at java.lang.reflect.Method.invokeNative(Native Method)
at java.lang.reflect.Method.invoke(Method.java:507)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:875)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:633)
at dalvik.system.NativeStart.main(Native Method)
Caused by: java.lang.ClassCastException: android.telephony.cdma.CdmaCellLocation
at com.xxx.xxx.xxx.ServiceLocation.location(ServiceLocation.java:83)
at com.xxx.xxx.xxx.ServiceLocation.onStartCommand(ServiceLocation.java:53)
at android.app.ActivityThread.handleServiceArgs(ActivityThread.java:2039)
... 10 more
GsmCellLocation cellLocation = (GsmCellLocation) telephonyManager.getCellLocation();
电话\类型\ SIP-设备正在使用SIP会话启动协议进行通信。getCellLocation将返回null。研究此问题，您可以使用TelephonyManager类的getPhoneType确定电话类型 我会尝试以下方法：
switch( telephonyManager.getPhoneType() ) {
case PHONE_TYPE_GSM: {
// Handle GSM phone
GsmCellLocation cellLocation = (GsmCellLocation) telephonyManager.getCellLocation();
break;
}
case PHONE_TYPE_CDMA: {
// Handle CDMA phone
CdmaCellLocation cellLocation = (CdmaCellLocation) telephonyManager.getCellLocation();
break;
}
default: {
// can't do cell location
}
研究这一点，您可以使用TelephonyManager类的getPhoneType确定电话类型 我会尝试以下方法：
switch( telephonyManager.getPhoneType() ) {
case PHONE_TYPE_GSM: {
// Handle GSM phone
GsmCellLocation cellLocation = (GsmCellLocation) telephonyManager.getCellLocation();
break;
}
case PHONE_TYPE_CDMA: {
// Handle CDMA phone
CdmaCellLocation cellLocation = (CdmaCellLocation) telephonyManager.getCellLocation();
break;
}
default: {
// can't do cell location
}
这是GsmCellLocation cellLocation=GsmCellLocation telephonyManager.getCellLocation；行ServiceLocation.locationServiceLocation.java:83？您是否在CDMA手机上测试了您的应用程序？是的，不，我不认为，我没有CDMA手机。我的猜测是，您需要确定它是哪种类型的手机，如果该设备是CDMA手机和您现有的GSM手机代码，则需要使用它。是的，如果这是CDMA手机，我将致电stopSelf，谢谢您的回答。关于屏幕？你是指屏幕截图中显示的错误报告中的亵渎吗？我真的不能回答这个问题，因为我对Android编程非常陌生，而且我还没有向Google Play发布任何应用程序。我的直觉是这可能不值得努力。如果你不打算支持CDMA手机，你应该在商店的帖子里写一条免责声明，以尽量减少挫折感。你有没有可能为CDMA手机添加CDMA码？您应该签出以测试您的GSM代码。这是GsmCellLocation cellLocation=GsmCellLocation telephonyManager.getCellLocation；行ServiceLocation.locationServiceLocation.java:83？您是否在CDMA手机上测试了您的应用程序？是的，不，我不认为，我没有CDMA手机。我的猜测是，您需要确定它是哪种类型的手机，如果该设备是CDMA手机和您现有的GSM手机代码，则需要使用它。是的，如果这是CDMA手机，我将致电stopSelf，谢谢您的回答。关于屏幕？你是指屏幕截图中显示的错误报告中的亵渎吗？我真的不能回答这个问题，因为我对Android编程非常陌生，而且我还没有向Google Play发布任何应用程序。我的直觉是这可能不值得努力。如果你不打算支持CDMA手机，你应该在商店的帖子里写一条免责声明，以尽量减少挫折感。你有没有可能为CDMA手机添加CDMA码？您应该结帐测试您的GSM代码。谢谢，这回答了我的问题。谢谢，这回答了我的问题。还有：
CDMA cid=cellLocation.getBaseStationLatitude；lac=cellLocation.GetBaseStationLongLevel；==此GSM cid=cellLocation.getCid；lac=cellLocation.getLac？我认为您的代码缺少每个案例末尾的break语句-这是：CDMA cid=cellLocation.getBaseStationLatitude；lac=cellLocation.GetBaseStationLongLevel；==此GSM cid=cellLocation.getCid；lac=cellLocation.getLac？我认为您的代码缺少每个案例末尾的break语句-