Android 如何在数组中包含的字符串中显示用户名
我不知道如何在第二个活动中显示上一个活动的用户名 我已经尝试了很多方法,但是没有一个能让我在字符串中显示用户名 这是主要的活动:Android 如何在数组中包含的字符串中显示用户名,android,arrays,string,android-edittext,Android,Arrays,String,Android Edittext,我不知道如何在第二个活动中显示上一个活动的用户名 我已经尝试了很多方法,但是没有一个能让我在字符串中显示用户名 这是主要的活动: private EditText nameField; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main);
private EditText nameField;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
nameField = findViewById(R.id.nameEditText);
Button startButton = findViewById(R.id.startButton);
startButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String name = nameField.getText().toString();
getusername(name);
}
});
}
private void getusername(String name) {
Intent intent = new Intent(this, OneShot.class);
Resources resources = getResources();
String key = resources.getString(R.string.key_name);
intent.putExtra(key, name);
startActivity(intent);
}
public static final String TAG = OneShot.class.getSimpleName();
private String name;
private int nextSentenceId = 0;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_one_shot);
Intent intent = getIntent();
name = intent.getStringExtra(getString(R.string.key_name));
if (name == null || name.isEmpty()) {
name = "Player";
}
Log.d(TAG, name);
final int[] sentences = new int[]{R.string.page0, R.string.page2, R.string.page3, R.string.page4, R.string.page5 };
Button next= findViewById(R.id.next);
final TextView displayText= findViewById(R.id.displayText);
next.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
final int limit = 5;
if(nextSentenceId < sentences.length){
displayText.setText(sentences[nextSentenceId]);
++nextSentenceId;
}
}
});
}
这是第二项活动:
private EditText nameField;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
nameField = findViewById(R.id.nameEditText);
Button startButton = findViewById(R.id.startButton);
startButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String name = nameField.getText().toString();
getusername(name);
}
});
}
private void getusername(String name) {
Intent intent = new Intent(this, OneShot.class);
Resources resources = getResources();
String key = resources.getString(R.string.key_name);
intent.putExtra(key, name);
startActivity(intent);
}
public static final String TAG = OneShot.class.getSimpleName();
private String name;
private int nextSentenceId = 0;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_one_shot);
Intent intent = getIntent();
name = intent.getStringExtra(getString(R.string.key_name));
if (name == null || name.isEmpty()) {
name = "Player";
}
Log.d(TAG, name);
final int[] sentences = new int[]{R.string.page0, R.string.page2, R.string.page3, R.string.page4, R.string.page5 };
Button next= findViewById(R.id.next);
final TextView displayText= findViewById(R.id.displayText);
next.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
final int limit = 5;
if(nextSentenceId < sentences.length){
displayText.setText(sentences[nextSentenceId]);
++nextSentenceId;
}
}
});
}
公共静态最终字符串标记=OneShot.class.getSimpleName();
私有字符串名称;
私有int NEXTSENTCEID=0;
@凌驾
创建时受保护的void(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_one_shot);
Intent=getIntent();
name=intent.getStringExtra(getString(R.string.key_name));
if(name==null | | name.isEmpty()){
name=“Player”;
}
Log.d(标签、名称);
final int[]句=新int[]{R.string.page0,R.string.page2,R.string.page3,R.string.page4,R.string.page5};
按钮next=findViewById(R.id.next);
最终文本视图显示文本=findViewById(R.id.displayText);
next.setOnClickListener(新视图.OnClickListener(){
@凌驾
公共void onClick(视图v){
最终整数限值=5;
if(nextContenceId<句长){
displayText.setText(句子[nextcontenceid]);
++下一个主题;
}
}
});
}
这些是int[]中的字符串:
<string name="page0"> Hello %1$s </string>
<string name="page2"> Welcome into this application </string>
<string name="page3"> How are you ? </string>
<string name="page4"> How is the weather </string>
<string name="page5"> Is %1$s you\'re real name ? </string>
您好%1$s
欢迎使用此应用程序
你好吗
天气怎么样
%1$s您是真名吗?
为什么用户名没有在字符串语句中传递?我如何修复它?提前感谢。您在
int
数组中拥有的不是字符串
值,而是用于链接到所述字符串
资源的ID。您可以使用getResources().getString(R.String.yourstring)
获取与id关联的String
资源(值)
更改:
<string name="page0">Hello %s</string>
<string name="page5">Is %s your real name?</string>