调用AsynchTask.get()时Android UI线程阻塞
我的活动是一个登录页面。当用户单击时,异步任务将检查数据库中的凭据是否良好。在任务期间,我想显示一个ProgressDialog,但单击按钮后,它保持按下5秒钟,然后我的ProgressDialog quiclky显示(不到1秒钟),并显示toast 这是我的onClick函数:调用AsynchTask.get()时Android UI线程阻塞,android,multithreading,android-asynctask,ui-thread,Android,Multithreading,Android Asynctask,Ui Thread,我的活动是一个登录页面。当用户单击时,异步任务将检查数据库中的凭据是否良好。在任务期间,我想显示一个ProgressDialog,但单击按钮后,它保持按下5秒钟,然后我的ProgressDialog quiclky显示(不到1秒钟),并显示toast 这是我的onClick函数: Button connect = (Button)findViewById(R.id.connectButton); final EditText loginED = (EditText) findViewById(R
Button connect = (Button)findViewById(R.id.connectButton);
final EditText loginED = (EditText) findViewById(R.id.login);
final EditText passwordED = (EditText) findViewById(R.id.password);
connect.setOnClickListener(new View.OnClickListener(){
@Override
public void onClick(View arg0) {
String login = loginED.getText().toString();
String password = passwordED.getText().toString();
String[] params = {login, password};
DoAsyncLogin doAsyncLogin = new DoAsyncLogin();
try {
String result = doAsyncLogin.execute(params).get();
Toast.makeText(MainActivity.this, result, Toast.LENGTH_LONG).show();
} catch (InterruptedException e) {
e.printStackTrace();
} catch (ExecutionException e) {
e.printStackTrace();
}
}
});
我的任务是:
private class DoAsyncLogin extends AsyncTask<String, Void, String>
{
ProgressDialog connectionProgressDialog = new ProgressDialog(MainActivity.this);
@Override
protected String doInBackground(String... params) {
return getLoginData(params);
}
protected void onPreExecute(){
connectionProgressDialog.setProgressStyle(ProgressDialog.STYLE_SPINNER);
connectionProgressDialog.setMessage("Logging in...");
connectionProgressDialog.show();
}
protected void onPostExecute(String result)
{
connectionProgressDialog.dismiss();
}
}
私有类DoAsyncLogin扩展了异步任务
{
ProgressDialog connectionProgressDialog=新建ProgressDialog(MainActivity.this);
@凌驾
受保护的字符串doInBackground(字符串…参数){
返回getLoginData(参数);
}
受保护的void onPreExecute(){
connectionProgressDialog.setProgressStyle(ProgressDialog.STYLE_微调器);
connectionProgressDialog.setMessage(“登录…”);
connectionProgressDialog.show();
}
受保护的void onPostExecute(字符串结果)
{
connectionProgressDialog.Disclose();
}
}
有什么想法吗
谢谢 问题在于,您正在等待(阻塞)异步任务在主线程上完成执行(这使得它无用): 请参阅此处有关AsynchTask get方法的文档: 相反,您应该使用
onpostExecute
回调以获取结果
代码:
在asynchTask中:
protected void onPostExecute(String result){
connectionProgressDialog.dismiss();
Toast.makeText(MainActivity.this, result, Toast.LENGTH_LONG).show();
}
protected void onPostExecute(String result){
connectionProgressDialog.dismiss();
Toast.makeText(MainActivity.this, result, Toast.LENGTH_LONG).show();
}