Angularjs 在$http.get中迭代
我有一段代码,每个请求显示20个项目Angularjs 在$http.get中迭代,angularjs,loops,http,get,Angularjs,Loops,Http,Get,我有一段代码,每个请求显示20个项目 .controller('ActorController',function($scope,$http) { $scope.getActors = function () { var actors = $http.get(https://api.themoviedb.org/3/person/popular&page=1); actors.then( function (respons
.controller('ActorController',function($scope,$http) {
$scope.getActors = function () {
var actors = $http.get(https://api.themoviedb.org/3/person/popular&page=1);
actors.then(
function (response) {
$scope.actors = response.data.results;
}
);
}
})
如果我把page=2,我将得到另一组20项,以此类推,而不是page=1。如果我希望在一个页面中有多个get请求,如何在$http.get中进行迭代?我想在显示第一个20项之后显示第二个20项。您可以使用$q.all一次发送多个http请求
var fulAr = [];
for (var i = 1; i <= 2; i++) {
fulAr.push($http.get("https://api.themoviedb.org/3/person/popular&page=" + i))
}
$q.all(fulAr).then(function(response) {
console.log(response[0].data) //page 1 content
console.log(response[1].data) //page 2 content
for(var j = 0; j < response.length; j++) {
$scope.actors = $scope.actors.concat(response[j].data.results);
}
})
确保将$q注入控制器所以您是说要在循环中多次调用$http.get?如果是这样,你会这样做:
.controller('ActorController',function($scope,$http) {
$scope.getActors = function () {
for(var i = 0; i < 5; i++) {
getPage(i);
}
}
function getPage(i) {
var actors = $http.get('https://api.themoviedb.org/3/person/popular&page=' + i);
actors.then(function (response) {
for(var j = 0; j < response.data.results.length; j++) {
$scope.actors.push(response.data.results[j]);
}
});
}
})
这将把前5页的数据放入$scope.actors数组。FYI,我认为@sachila ranawaka的答案可能更好。@SJ94再次检查答案。非常感谢。