Apache camel Apache Camel服务器应用程序接收多部分表单POST（文件上载）

我正在使用Camel servlet组件来接收xml文档，现在我还需要接收文件JPEG、GIF等。下面是我的客户端应用程序发送文件的方式：

import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.mime.MultipartEntity;
import org.apache.http.entity.mime.content.FileBody;
import org.apache.http.impl.client.DefaultHttpClient;

public class HttpClientUploadHelper {
    public boolean upload(final File file, final String url) {
        boolean wasSent = false ;
        HttpClient client = new DefaultHttpClient();
        HttpPost post = new HttpPost(url);
        MultipartEntity entity = new MultipartEntity();
        entity.addPart(file.getName(), new FileBody(file));
        post.setEntity(entity);
        try {
            HttpResponse response = client.execute(post);
            wasSent = response.getStatusLine().getStatusCode()==200;
        } catch (Exception e) {
        }
        return wasSent;
    }
}

然后，我的Camel处理器通过以下方式提取HttpServletRequest：

HttpServletRequest req = exchange.getIn().getHeader(Exchange.HTTP_SERVLET_REQUEST, HttpServletRequest.class);

然后我有了这个方法来最终解析并保存文件：

import org.apache.commons.fileupload.FileItemFactory;
import org.apache.commons.fileupload.FileItemIterator;
import org.apache.commons.fileupload.FileItemStream;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
import org.apache.commons.io.IOUtils

... class declaration, body, etc...

void parseAndSaveFile(final HttpServletRequest req) throws Exception {
    // Check that we have a file upload request 
    boolean isMultipart = ServletFileUpload.isMultipartContent(req);
    // Create a factory for disk-based file items
    FileItemFactory factory = new DiskFileItemFactory();
    // Create a new file upload handler
    ServletFileUpload upload = new ServletFileUpload(factory);
    // Parse the request
    FileItemIterator receivedFiles =  upload.getItemIterator(req);
    while (receivedFiles.hasNext()) {
          FileItemStream file = receivedFiles.next();
          if (file.isFormField()) {
            System.out.println("WTF?");
          } else {
            String fileName = file.getName();
            File uploadedFile = new File("/home/myuser/" + fileName);
            FileOutputStream out = new FileOutputStream(uploadedFile);
            IOUtils.copy(file.openStream(), out);
        }
    }
}

当我在Camel中使用上述代码时，isMultipart标志为true，但receivedFiles迭代器不包含任何元素。当我在另一个只有普通servlet的项目中使用上述代码时，代码就起作用了。在这两方面，我都使用jetty作为web容器

那么，在我的camel处理器中，还有其他方法提取文件名及其内容吗

---

谢谢

既然您使用的是Jetty，您是否考虑过使用附带的MultipartFilter而不是FileUpload项目？超级清洁，易于使用

从javadoc：

此类对使用文件输入项的HTML表单发送的多部分/表单数据流进行解码。发送的任何文件都存储到临时文件中，并将文件对象作为属性添加到请求中。所有其他值都可以通过普通的getParameter API获得，并且在将字节转换为字符串时，遵守setCharacterEncoding机制。

这有帮助吗

public void process(Exchange exchange) throws Exception { Message in = exchange.getIn(); Set names = in.getAttachmentNames(); for(String n: names) { System.out.println("attachment "+n); DataHandler h = in.getAttachment(n); if(h!=null) { try { Object o = h.getContent(); System.out.println(o); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); } } } if(!names.isEmpty()) return; }