Apache spark 无法在Spark SQL中生成UUID

下面是收到的代码块和错误

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我正在尝试生成UUID，但是得到了这个错误

下面是一个简单的示例，说明如何生成timeuuid：

import org.apache.spark.sql.SQLContext    
val sqlcontext = new SQLContext(sc)

import sqlcontext.implicits._

//Import UUIDs that contains the method timeBased()
import com.datastax.driver.core.utils.UUIDs

//user define function timeUUID  which will retrun time based uuid      
val timeUUID = udf(() => UUIDs.timeBased().toString)

//sample query to test, you can change it to yours
val df_newrecords = sqlcontext.sql("SELECT 1 as data UNION SELECT 2 as data").withColumn("time_uuid", timeUUID())

//print all the rows
df_newrecords.collect().foreach(println)

输出：

[1,9a81b3c0-170b-11e7-98bf-9bb55f3128dd]
[2,9a831350-170b-11e7-98bf-9bb55f3128dd]

资料来源：

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检查此答案谢谢@AshrafulIslam，在尝试答案时出现以下错误。scala>val-sqlContext=new-sqlContext（sc）警告：有一个弃用警告；有关详细信息，请使用-deprecation重新运行sqlContext:org.apache.spark.sql.sqlContext=org.apache.spark.sql。SQLContext@39ab2bf3scala>scala>import sqlContext.implicits.\uImport sqlContext.implicits.\uScala>val generateUUID=udf（（）=>UUID.randomUUID（）.toString）：46:错误：未找到：值UUID val generateUUID=udf（）=>UUID.randomUUID（）.toString）^目前，我已经使用了在源代码处生成UUID并在执行scd 2操作时使用它们的变通方法。

import org.apache.spark.sql.SQLContext    
val sqlcontext = new SQLContext(sc)

import sqlcontext.implicits._

//Import UUIDs that contains the method timeBased()
import com.datastax.driver.core.utils.UUIDs

//user define function timeUUID  which will retrun time based uuid      
val timeUUID = udf(() => UUIDs.timeBased().toString)

//sample query to test, you can change it to yours
val df_newrecords = sqlcontext.sql("SELECT 1 as data UNION SELECT 2 as data").withColumn("time_uuid", timeUUID())

//print all the rows
df_newrecords.collect().foreach(println)

[1,9a81b3c0-170b-11e7-98bf-9bb55f3128dd]
[2,9a831350-170b-11e7-98bf-9bb55f3128dd]