Arrays 自定义类的字典数组
我已经成功地将我的Firebase数据拉入字典,但是我很难将这些值放入我的自定义类中 要从Firebase获取数据,我使用以下代码:Arrays 自定义类的字典数组,arrays,dictionary,firebase,swift3,completionhandler,Arrays,Dictionary,Firebase,Swift3,Completionhandler,我已经成功地将我的Firebase数据拉入字典,但是我很难将这些值放入我的自定义类中 要从Firebase获取数据,我使用以下代码: func testing(completion: @escaping ([String : Any]) -> ()) { ref.child("dailyJobs").observe(.childAdded, with: { (snapshot) in if let value = snapshot.value as? [Strin
func testing(completion: @escaping ([String : Any]) -> ()) {
ref.child("dailyJobs").observe(.childAdded, with: { (snapshot) in
if let value = snapshot.value as? [String : Any] {
completion(value as [String : Any])
return
}
completion([:])
})
}
当我调用函数时
testing { (dictionary) in
print(dictionary)
}
我从Firebase得到的字典如下(它是一组字典):
我的自定义类是:
class JobsAndHabits {
var name: String
var multiplier: Double
var assigned: String
var order: Int
init(jobName: String, jobMultiplier: Double, jobAssign: String, jobOrder: Int) {
self.name = jobName
self.multiplier = jobMultiplier
self.assigned = jobAssign
self.order = jobOrder
}
我解析词典的代码如下:
testing { (dictionary) in
for item in dictionary {
print(item)
let multiplier = dictionary["multiplier"] as! Double
let name = dictionary["name"] as! String
let assigned = dictionary["assigned"] as! String
let order = dictionary["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
}
print(self.dailyJobs)
我得到的是:
[ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits]
每本字典有4本。不知何故,我的代码将数组复制了4倍,现在我的头很痛。我相信有一个简单的解决办法
我也尝试过:
将所有代码放入原始闭包中,如下所示:
func loadExistingJobs(_ completion: @escaping () -> ()) {
ref.child("dailyJobs").observe(.childAdded, with: { (snapshot) in
if let dictionary = snapshot.value as? [String : Any] {
let multiplier = dictionary["multiplier"] as! Double
let name = dictionary["name"] as! String
let assigned = dictionary["assigned"] as! String
let order = dictionary["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
self.dailyJobs.sort(by: {$0.order < $1.order})
self.jobsTableView.reloadData()
completion()
}
})
func加载现有作业(u完成:@escaping()->()){
ref.child(“dailyJobs”).observe(.childAdded,在
如果let dictionary=snapshot.value as?[字符串:Any]{
让乘数=字典[“乘数”]为!双精度
让name=dictionary[“name”]作为!字符串
设assigned=dictionary[“assigned”]为!字符串
让order=dictionary[“order”]as!Int
让dailyJob=JobsAndHabits(jobName:name,Job乘数:乘数,jobAssign:assigned,jobOrder:order)
self.dailyJobs.append(dailyJob)
self.dailyJobs.sort(按:{$0.order<$1.order})
self.jobsTableView.reloadData()
完成()
}
})
但是@escaping
闭包没有正常运行,我的后续代码也没有执行
TL;DR-我想从Firebase中提取数据并将其附加到我的阵列中。请检查:
你的字典是[“name”:自定义杂务列表,“multiplier”:1,“assigned”:none,“order”:0]
,你正在为此编写循环。它有4个键,因此循环4次
如果您的字典类似于[String:Any],那么您必须调用如下代码:
testing { (dictionary) in
let multiplier = Double(dictionary["multiplier"] as! Int)
let name = dictionary["name"] as! String
let assigned = dictionary["assigned"] as! String
let order = dictionary["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
print(self.dailyJobs)
})
func testing(completion: @escaping ([[String : Any]]) -> ()) {
let dictionary = [[String: Any]]
ref.child("dailyJobs").observe(.childAdded, with: { (snapshot) in
for child in (snapshot?.children)! {
let snap = child as! FDataSnapshot //each child is a snapshot
if let value = snap.value as? [String : Any] {
dictionary.append(value)
}
}
completion(dictionary)
})
}
testing { (dictionary) in
for item in dictionary {
print(item)
let multiplier = Double(item["multiplier"] as! Int)
let name = item["name"] as! String
let assigned = item["assigned"] as! String
let order = item["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
// }
print(self.dailyJobs)
}
})
如果您的字典类似于[[String:Any]],那么您必须按如下方式调用:
testing { (dictionary) in
let multiplier = Double(dictionary["multiplier"] as! Int)
let name = dictionary["name"] as! String
let assigned = dictionary["assigned"] as! String
let order = dictionary["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
print(self.dailyJobs)
})
func testing(completion: @escaping ([[String : Any]]) -> ()) {
let dictionary = [[String: Any]]
ref.child("dailyJobs").observe(.childAdded, with: { (snapshot) in
for child in (snapshot?.children)! {
let snap = child as! FDataSnapshot //each child is a snapshot
if let value = snap.value as? [String : Any] {
dictionary.append(value)
}
}
completion(dictionary)
})
}
testing { (dictionary) in
for item in dictionary {
print(item)
let multiplier = Double(item["multiplier"] as! Int)
let name = item["name"] as! String
let assigned = item["assigned"] as! String
let order = item["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
// }
print(self.dailyJobs)
}
})
请检查:
你的字典是[“name”:自定义杂务列表,“multiplier”:1,“assigned”:none,“order”:0]
,你正在为此编写循环。它有4个键,因此循环4次
如果您的字典类似于[String:Any],那么您必须调用如下代码:
testing { (dictionary) in
let multiplier = Double(dictionary["multiplier"] as! Int)
let name = dictionary["name"] as! String
let assigned = dictionary["assigned"] as! String
let order = dictionary["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
print(self.dailyJobs)
})
func testing(completion: @escaping ([[String : Any]]) -> ()) {
let dictionary = [[String: Any]]
ref.child("dailyJobs").observe(.childAdded, with: { (snapshot) in
for child in (snapshot?.children)! {
let snap = child as! FDataSnapshot //each child is a snapshot
if let value = snap.value as? [String : Any] {
dictionary.append(value)
}
}
completion(dictionary)
})
}
testing { (dictionary) in
for item in dictionary {
print(item)
let multiplier = Double(item["multiplier"] as! Int)
let name = item["name"] as! String
let assigned = item["assigned"] as! String
let order = item["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
// }
print(self.dailyJobs)
}
})
如果您的字典类似于[[String:Any]],那么您必须按如下方式调用:
testing { (dictionary) in
let multiplier = Double(dictionary["multiplier"] as! Int)
let name = dictionary["name"] as! String
let assigned = dictionary["assigned"] as! String
let order = dictionary["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
print(self.dailyJobs)
})
func testing(completion: @escaping ([[String : Any]]) -> ()) {
let dictionary = [[String: Any]]
ref.child("dailyJobs").observe(.childAdded, with: { (snapshot) in
for child in (snapshot?.children)! {
let snap = child as! FDataSnapshot //each child is a snapshot
if let value = snap.value as? [String : Any] {
dictionary.append(value)
}
}
completion(dictionary)
})
}
testing { (dictionary) in
for item in dictionary {
print(item)
let multiplier = Double(item["multiplier"] as! Int)
let name = item["name"] as! String
let assigned = item["assigned"] as! String
let order = item["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
// }
print(self.dailyJobs)
}
})
嘿,你可以试试这个代码,并根据需要修改
class JobsAndHabits {
var name: String
var multiplier: Double
var assigned: String
var order: Int
init(jobName: String, jobMultiplier: Double, jobAssign: String, jobOrder: Int) {
self.name = jobName
self.multiplier = jobMultiplier
self.assigned = jobAssign
self.order = jobOrder
}
class func getAllJobsAndHabbits(forUserID userID: String, completion: @escaping (JobsAndHabits) -> Swift.Void, failure: @escaping () -> ()) {
if Auth.auth().currentUser != nil {
Database.database().reference().child("jobsAndHabits").child(userID).observe(.childAdded, with: { (snapshot) in
if snapshot.exists() {
let receivedMessage = snapshot.value as! [String: Any]
let name = receivedMessage["content"] as? String ?? ""
let multiplier = receivedMessage["multiplier"] as? Double ?? 0.0
let assigned = receivedMessage["assigned"] as? String ?? ""
let order = receivedMessage["order"] as? Int ?? 0
completion(JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order))
} else {
failure()
}
})
} else {
failure()
}
}
}
呼叫和处理的方式
class Test {
let dailyJobs:[JobsAndHabits] = []
JobsAndHabits.getAllJobsAndHabbits(forUserID: "12346", completion: {
self.dailyJobs.append(dailyJob)
self.dailyJobs.sort(by: {$0.order < $1.order})
}) {
//handle error
}
}
类测试{
让dailyJobs:[工作和习惯]=[]
JobsandHabbits.getAllJobsAndHabbits(用于用户ID:“12346”,完成:{
self.dailyJobs.append(dailyJob)
self.dailyJobs.sort(按:{$0.order<$1.order})
}) {
//处理错误
}
}
嘿,您可以尝试此代码,并根据需要进行修改
class JobsAndHabits {
var name: String
var multiplier: Double
var assigned: String
var order: Int
init(jobName: String, jobMultiplier: Double, jobAssign: String, jobOrder: Int) {
self.name = jobName
self.multiplier = jobMultiplier
self.assigned = jobAssign
self.order = jobOrder
}
class func getAllJobsAndHabbits(forUserID userID: String, completion: @escaping (JobsAndHabits) -> Swift.Void, failure: @escaping () -> ()) {
if Auth.auth().currentUser != nil {
Database.database().reference().child("jobsAndHabits").child(userID).observe(.childAdded, with: { (snapshot) in
if snapshot.exists() {
let receivedMessage = snapshot.value as! [String: Any]
let name = receivedMessage["content"] as? String ?? ""
let multiplier = receivedMessage["multiplier"] as? Double ?? 0.0
let assigned = receivedMessage["assigned"] as? String ?? ""
let order = receivedMessage["order"] as? Int ?? 0
completion(JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order))
} else {
failure()
}
})
} else {
failure()
}
}
}
呼叫和处理的方式
class Test {
let dailyJobs:[JobsAndHabits] = []
JobsAndHabits.getAllJobsAndHabbits(forUserID: "12346", completion: {
self.dailyJobs.append(dailyJob)
self.dailyJobs.sort(by: {$0.order < $1.order})
}) {
//handle error
}
}
类测试{
让dailyJobs:[工作和习惯]=[]
JobsandHabbits.getAllJobsAndHabbits(用于用户ID:“12346”,完成:{
self.dailyJobs.append(dailyJob)
self.dailyJobs.sort(按:{$0.order<$1.order})
}) {
//处理错误
}
}
是的,那么我该如何避免呢?我被难住了。我该如何将这四个键放入我的一类对象中?请检查我的代码。删除循环。现在您将得到正确的结果。崩溃。在第1行展开可选值时意外地发现了零:让乘数=字典…
否。您正在尝试将任何值转换为零uble。所以它失败了。你的乘数是双倍的,它在字典中的值是Int。好的。修复了。但是现在数据仍然在填充,即使我调用了代码。当我打印到控制台dailyJobs.count
,我得到1,2,3,4,5,6,7,8,9,10
。这意味着代码仍然在运行。它应该是10
。我的完成处理程序错了吗?是的,那么我该如何避免?我很困惑。我该如何将这四个键放入我的一个类对象中?请检查我的代码。为循环删除。现在你将得到正确的结果。崩溃。在第1行展开可选值时意外地发现了nil:让乘数=字典…
不。您正在尝试将任何值转换为双精度。因此,它失败了。您的乘法器是双精度的,并且它在字典中的值是Int。好的。得到了修复。但现在,即使在我调用代码之后,数据仍然填充。当我打印到控制台日常作业。计数时,我得到1、2、3、4、5、6、7、8、9、10
。这意味着代码仍在运行。它应该是10
。我的完成处理程序是否错误?Hmmm..dailyJobs
仍在异步加载。我希望在来自数据库的最后一次调用上运行代码,而不是以增量方式运行代码。您知道,我希望根据dailyJobs
列表追加另一个数组。Hmmm..dailyJobs
仍在运行异步加载。我希望对来自数据库的最后一个调用运行代码,而不是以增量方式运行。您知道,我希望根据dailyJobs
列表附加另一个数组。