Arrays 将字符串数组描述转换为数组

我有以下代码：

var data = [12,33,22,44];
var a =  data.description;  // results is "[12,33,22,44]"
var new = Array(a); // result is ['[','1'.  not [12,33,22,44]

除了拆分“a”和迭代结果之外，还有一种最快的方法可以将字符串转换为数组吗

谢谢

你可以

• 将

  [

  和

  ]

  字符修剪为

  stringByTrimmingCharactersInSet

• 将其拆分为由逗号分隔的组件数组；及
• 修剪每个项目周围的空白

例如：

let array = [12,33,22,44];
let string = array.description;  // result is "[12, 33, 22, 44]", not "[12,33,22,44]"

let results = string
    .stringByTrimmingCharactersInSet(NSCharacterSet(charactersInString: "[]"))
    .componentsSeparatedByString(",")
    .map { return $0.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet()) }

或者，如果需要整数数组而不是字符串数组：

let results = string
    .stringByTrimmingCharactersInSet(NSCharacterSet(charactersInString: "[]"))
    .componentsSeparatedByString(",")
    .map { return $0.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet()).toInt()! }  // remove `!` if you're not assured that only integers will be present

你可以

• 将

  [

  和

  ]

  字符修剪为

  stringByTrimmingCharactersInSet

• 将其拆分为由逗号分隔的组件数组；及
• 修剪每个项目周围的空白

例如：

let array = [12,33,22,44];
let string = array.description;  // result is "[12, 33, 22, 44]", not "[12,33,22,44]"

let results = string
    .stringByTrimmingCharactersInSet(NSCharacterSet(charactersInString: "[]"))
    .componentsSeparatedByString(",")
    .map { return $0.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet()) }

或者，如果需要整数数组而不是字符串数组：

let results = string
    .stringByTrimmingCharactersInSet(NSCharacterSet(charactersInString: "[]"))
    .componentsSeparatedByString(",")
    .map { return $0.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet()).toInt()! }  // remove `!` if you're not assured that only integers will be present

---

您可以通过拆分数组并过滤所有无法转换为

Int

的元素来实现这一点

 "[12,33,22,44]".componentsSeparatedByCharactersInSet(NSCharacterSet(charactersInString: "[,]")).filter{ $0.toInt() != nil }.map{ $0.toInt()! } // [12, 33, 22, 44]

---

您可以通过拆分数组并过滤所有无法转换为

Int

的元素来实现这一点

 "[12,33,22,44]".componentsSeparatedByCharactersInSet(NSCharacterSet(charactersInString: "[,]")).filter{ $0.toInt() != nil }.map{ $0.toInt()! } // [12, 33, 22, 44]

---

罗布对Swift 2.2的回答

let results = value
            .stringByTrimmingCharactersInSet(NSCharacterSet(charactersInString: "[]"))
            .componentsSeparatedByString(",")
            .map { return Int($0.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet()))!}  // remove `!` if you're not assured that only integers will be present

---

罗布对Swift 2.2的回答

let results = value
            .stringByTrimmingCharactersInSet(NSCharacterSet(charactersInString: "[]"))
            .componentsSeparatedByString(",")
            .map { return Int($0.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet()))!}  // remove `!` if you're not assured that only integers will be present

---

一种安全的方法是将字符串编码为数据，然后将数据解码为JSON，最后将结果向下转换为整数数组：

let base = [12,33,22,44]
let source = base.description
if let data = source.dataUsingEncoding(NSUTF8StringEncoding) {
    if let arrayOfInts = try NSJSONSerialization.JSONObjectWithData(data, options: []) as? [Int] {
        print(arrayOfInts) // [12, 33, 22, 44]
        print(arrayOfInts[1]) // 33
    }
}

---

一种安全的方法是将字符串编码为数据，然后将数据解码为JSON，最后将结果向下转换为整数数组：

let base = [12,33,22,44]
let source = base.description
if let data = source.dataUsingEncoding(NSUTF8StringEncoding) {
    if let arrayOfInts = try NSJSONSerialization.JSONObjectWithData(data, options: []) as? [Int] {
        print(arrayOfInts) // [12, 33, 22, 44]
        print(arrayOfInts[1]) // 33
    }
}

Swift 3代码：

let results = "[12,33,22,44]"
              .trimmingCharacters(in: CharacterSet(charactersIn: "[]"))
              .components(separatedBy:",")

print("Result array: \(results)")

Swift 3代码：

let results = "[12,33,22,44]"
              .trimmingCharacters(in: CharacterSet(charactersIn: "[]"))
              .components(separatedBy:",")

print("Result array: \(results)")

---

实际上变量

data

是一个数组。我想他想要一个只提供数组描述的方案。实际上变量

data

是一个数组。我想他想要一个只提供数组描述的方案。