Arrays 将n个值相加，在Powershell中得到x

我有一个值数组（大约20个），范围从大约

9.5

到

0.001

。我需要将这些值相加，得到15到85之间的任意数字（或尽可能得到最接近的值）

测试数据：

[9.912,7.414,5.512, 5.43,5.303,5.041,5.025,4.944,3.509,  3.3,3.191,3.076,2.914,2.753, 2.29,1.955,1.917,1.822,1.626,1.526,1.489,1.482,1.362,1.354,1.311,1.222,1.154,0.904,0.799, 0.79,0.657,0.643,0.618,0.615,0.592,0.564,0.484, 0.48,0.447,0.419,0.415,0.328,0.325,0.288, 0.26,0.251,0.248,0.23,0.223,0.221,0.154,0.129,0.128,0.126,0.103,0.102,0.099,0.092,0.077,0.071,0.066, 0.06,0.046,0.037,0.028,0.023,0.007,0.003,0.003,0.003,0.002,0.001,0.001,0.001,0.001]

---

有人能帮我吗/这可能吗？

你可以这样做：

$arr = @(9.912,7.414,5.512, 5.43,5.303,5.041,5.025,4.944,3.509,  3.3,3.191,3.076,2.914,2.753, 2.29,1.955,1.917,1.822,1.626,1.526,1.489,1.482,1.362,1.354,1.311,1.222,1.154,0.904,0.799, 0.79,0.657,0.643,0.618,0.615,0.592,0.564,0.484, 0.48,0.447,0.419,0.415,0.328,0.325,0.288, 0.26,0.251,0.248,0.23,0.223,0.221,0.154,0.129,0.128,0.126,0.103,0.102,0.099,0.092,0.077,0.071,0.066, 0.06,0.046,0.037,0.028,0.023,0.007,0.003,0.003,0.003,0.002,0.001,0.001,0.001,0.001)

$output = 0
$arr | foreach {
    if(($output + $_) -le 85){
        $output += $_
    }
}

$output

---

上面的示例将返回一个接近但小于85的数字

您没有显示任何自己的代码或任何您尝试研究/搜索解决方案的迹象。（即使代码不起作用，也要始终包含它！）我建议阅读，因为此时您的问题缺少了提问时所需的基本知识。你的问题可能会被否决并关闭，直到你包含了基本内容。我觉得这看起来像是一个课堂作业问题……是的，我下次会这样做。我的主要问题是，我根本不知道如何处理这个问题（因此没有代码）。现在我看到了雨篷，它看起来很清晰！你的问题模棱两可。距离范围15到85最近的值？目标是什么，范围的下限/上限？或者得到一个精确的整数值？为了匹配不同的值，回溯算法可能会找到更好的值，而不仅仅是按顺序累加。