Asp.net mvc 编辑结果LINQ到实体

我有一张名为“客户”的桌子和另一张名为“地址”的桌子，所以我想这样做：

我想在消费者和地址上选择，并在下拉列表中填入customers.Name和Address.Street字段。下拉列表如下所示：

Jack Jhonsom-蒙大拿州 罗伯特·巴尔默-华盛顿特区 玛丽亚本德利-摩根敦

我怎么做

我正在使用ASP.NET MVC 4 RAZOR，实体框架已更新

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可能是其中一种解决方案将有助于：

List<SelectListItem> result;

//**If you have relation Customer.Address
var customers = db.Customers.ToList();

var items = (from n in customers 
             select new SelectListItem
             {
               text = String.Format("{0}-{1}", n.Name, n.Address.City),
               value = n.customerID.ToString();
             }).ToList();
result.AddRange(items);

return result;

//If you don't have relation Customer.Address
var customers = db.Customers.ToList();
var addresses = db.Addresses.ToList();
var items = (from n in customers
             join b in addresses on b.addressid equals n.addressid
             select new SelectListItem
             {
               text = String.Format("{0}-{1}", n.Name, b.City),
               value = n.customerID.ToString();
             }).ToList();
result.AddRange(items);

return result;

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我只有以下代码：var query=from c in ctx.customers选择c.Name；查询包含要在下拉列表中显示的名称列表，对吗？Aviran，但我的问题不在于如何显示它，而是如何使用LINQ to实体构建一个查询，该实体统一了两个字段customers.Name和address.Street。如我构建的示例：NAME+-+address请提供您的类结构，以便我可以提供帮助

List<SelectListItem> result;

//**If you have relation Customer.Address
var customers = db.Customers.ToList();

var items = (from n in customers 
             select new SelectListItem
             {
               text = String.Format("{0}-{1}", n.Name, n.Address.City),
               value = n.customerID.ToString();
             }).ToList();
result.AddRange(items);

return result;

//If you don't have relation Customer.Address
var customers = db.Customers.ToList();
var addresses = db.Addresses.ToList();
var items = (from n in customers
             join b in addresses on b.addressid equals n.addressid
             select new SelectListItem
             {
               text = String.Format("{0}-{1}", n.Name, b.City),
               value = n.customerID.ToString();
             }).ToList();
result.AddRange(items);

return result;