如何告诉awk使用=作为分隔符（同时删除空格）

假设我有以下文件

John=good
Tom   = ok
Tim =    excellent

我知道以下内容，让我们使用

=

作为分隔符

awk -F= '{print $1,$2}' file

这给了我以下结果

John good
Tom     ok
Tim      excellent

我希望空白被忽略，这样只有名字和他们的表演被打印出来

解决这个问题的一种方法是对结果运行另一个

awk

awk -F= '{print$1,$2}' file | awk '{print $1,$2}'

---

但是我想知道我是否可以在一个

awk

？

中将它们包含在分隔符定义中；这是一个regexp

jinx:1654 Z$ awk -F' *= *' '{print $1, $2}' foo.ds
John good
Tom ok
Tim excellent

---

将其包含在分隔符定义中；这是一个regexp

jinx:1654 Z$ awk -F' *= *' '{print $1, $2}' foo.ds
John good
Tom ok
Tim excellent

---

FS变量可以设置为正则表达式

来自AWK手册

The following table summarizes how fields are split, based on the value of FS.

FS == " "
    Fields are separated by runs of whitespace. Leading and trailing whitespace are ignored. This is the default. 
FS == any single character
    Fields are separated by each occurrence of the character. Multiple successive occurrences delimit empty fields, as do leading and trailing occurrences. 
FS == regexp
    Fields are separated by occurrences of characters that match regexp. Leading and trailing matches of regexp delimit empty fields. 

---

FS变量可以设置为正则表达式

来自AWK手册

The following table summarizes how fields are split, based on the value of FS.

FS == " "
    Fields are separated by runs of whitespace. Leading and trailing whitespace are ignored. This is the default. 
FS == any single character
    Fields are separated by each occurrence of the character. Multiple successive occurrences delimit empty fields, as do leading and trailing occurrences. 
FS == regexp
    Fields are separated by occurrences of characters that match regexp. Leading and trailing matches of regexp delimit empty fields.