Awk 使用FPAT Var删除逗号后的空格

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 BEGIN {
         FPAT="([^,]+)|(\"[^\"]+\")"
 }
 {
 print "NF = ", NF
 for (i = 1; i <= NF; i++) {
         printf("$%d = <%s>\n", i, $i)}
 }

预期产量

NF =  3
$1 = <Johny Bravo>
$2 = <Chief of Security>
$3 = <417-555-66>

NF=3
$1 = 
$2 = 
$3 = 

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您可以在

for

循环中调用

gsub

，以删除每个字段的前导空格和尾随空格

s='Johny Bravo, Chief of Security, 417-555-66'

awk -v FPAT='("[^"]+")"|[^,]+' '{
   for (i = 1; i <= NF; i++) {
      gsub(/^ +| +$/, "", $i)
      printf("$%d = <%s>\n", i, $i)
   }
}' <<< "$s"

s='Johny Bravo，安全总监，417-555-66'
awk-v FPAT='（“[^”]+”）|[^，]+'{
对于（i=1；i
NF =  3
$1 = <Johny Bravo>
$2 = <Chief of Security>
$3 = <417-555-66>

s='Johny Bravo, Chief of Security, 417-555-66'

awk -v FPAT='("[^"]+")"|[^,]+' '{
   for (i = 1; i <= NF; i++) {
      gsub(/^ +| +$/, "", $i)
      printf("$%d = <%s>\n", i, $i)
   }
}' <<< "$s"

$1 = <Johny Bravo>
$2 = <Chief of Security>
$3 = <417-555-66>