awk无法删除特定列中的新行字符

我正在尝试使用awk删除csv文件第一列中的换行符，但它似乎不起作用

示例文件：

  "This
  is a test
  ","Something","Something"
  "This is
  another
  test","something","something"
  "One
  more
  test","something","something"

我使用的命令是

awk -F, '{gsub("\n","",$1); print}' sample

输出不会删除新行字符

我正在寻找一个使用awk而不是sed或perl的解决方案

有人能帮忙吗

所需的输出是

"This is a test","something","something"
"This is another test","something","something"
"One more test","something","something"

---

假设您拥有的是从Excel或其他一些windows工具导出的CSV（因为它看起来就是这样），因此它有

\r\n

行结尾，您所需要的就是GNU awk用于多字符：

$ awk -v RS='\r\n' -F'\n' '{$1=$1}1' file
"This is a test ","Something","Something"
"This is another test","something","something"
"One more test","something","something"

否则，对于GNU awk for multi char RS，这将适用于您发布的示例：

$ awk -v RS='"\\s+("|$)' -F'\n' '{$1=$1; gsub(/^"?|"?$/,"\"")}1' file
"This is a test ","Something","Something"
"This is another test","something","something"
"One more test","something","something"

---

展示最终的结果我试过了，它仍然在向我展示同一行中的所有内容。当我进行八进制转储时，我没有看到回车。那么我对您输入的假设是错误的。你从哪里得到这样的CSV？无论如何，我已经添加了一个适用于您的示例的gawk脚本。您可以在以csv格式导出windows事件日志时创建类似的csv文件。某些事件的描述包含多行类似于我上面指定的格式。我从未听说过任何Windows工具创建CSV或任何其他没有

\r\n

行结尾的文本文件，您确定没有在其上运行

dos2unix

或类似命令吗？这是我用来生成CSV文件的命令，$start=Get Date-Day-12-Month 03-Year 2017$end=Get Date-Day-16-Month 03-Year 2017 Get WinEvent-FilterHashtable@{Logname=“System”；starttime=$start；endtime=$end；}导出Csv-路径c:\System-$（主机名）.Csv