Azure devops Azure管道任务输入赢得';不接受变量
在azure管道yaml文件中,变量Azure devops Azure管道任务输入赢得';不接受变量,azure-devops,yaml,azure-pipelines,azure-pipelines-tasks,Azure Devops,Yaml,Azure Pipelines,Azure Pipelines Tasks,在azure管道yaml文件中,变量imgRepoName从gitRepoName中删除。所示为core/cqbapi的gitRepoName的bash回音;显示的imgRepoName的bash回显cqb api variables: vmImageName: 'ubuntu-18.04' gitRepoName: $(Build.Repository.Name) imgRepoName: $(basename $(gitRepoName)) - job: build_pus
imgRepoName
从gitRepoName
中删除。所示为core/cqbapi
的gitRepoName
的bash回音;显示的imgRepoName
的bash回显cqb api
variables:
vmImageName: 'ubuntu-18.04'
gitRepoName: $(Build.Repository.Name)
imgRepoName: $(basename $(gitRepoName))
- job: build_push_image
pool:
vmImage: $(vmImageName)
steps:
- task: Docker@2
displayName: Build and Push image
inputs:
repository: imgRepoName
command: buildAndPush
containerRegistry: "coreContainerRegistry"
tags: test2
问题:
当我编写存储库时:“cqbapi”
作为docker任务的输入,它工作得很好,而直接使用变量(如上所示)不会在容器注册表中创建任何图像
另外,我还尝试了repository:$(imgRepoName)
它给出了以下错误
invalid argument "***/$(basenamecore/cqb-api):test2" for "-t, --tag" flag: invalid reference format
看起来它是在运行时执行的。因此,将替换
gitreponame
,但在此上下文中无法识别basename函数。您可以检查以下内容:
variables:
gitRepoName: $(Build.Repository.Name)
steps:
- task: PowerShell@2
inputs:
targetType: 'inline'
script: |
$name = $(basename $(gitRepoName))
Write-Host "##vso[task.setvariable variable=imgRepoName]$name"
- task: Docker@2
displayName: Build and Push
inputs:
repository: $(imgRepoName)
command: build
Dockerfile: docker-multiple-apps/Dockerfile
tags: |
build-on-agent
这对我有用。你的问题解决了吗?你可能认为这是解决你问题的最好办法。