Backbone.js 主干继承，合并render（）函数

所以我现在的情况是：

app.Ui.ModalView = Backbone.View.extend({
    events: {

    },

    initialize: function() {

    },

    render: function() {
        var that = this;
        var model = this.model.toJSON();

        that.$el.html(that.template(_.extend(this.params || {}, {
            model: model,
        })));
        return this;
    }
});

然后是继承的视图：

app.Views.childView = kf.Ui.ModalView.extend({

    template: JST["templates/app/blah/blah-edit.html"],
    events: {

    },
    initialize: function() {
        var that = this;
        this.events = _.extend({}, app.Ui.ModalView.prototype.events, this.events);
        app.Ui.ModalView.prototype.initialize.apply(this, arguments);
    },

render: function(){
// add extra logic in this render function, to run as well as the inherited render function?
}

});

---

因此，我不想覆盖父级的

render（）

，但要向它添加额外的功能，我该如何做呢？

有两种方法可以实现这一点：要么通过在基类中创建“render hook”来添加显式支持来覆盖行为，或者，您必须从超类方法调用重写的基方法：

基类中的渲染挂钩：

app.Ui.ModalView = Backbone.View.extend({
  render: function() {
    //if this instance (superclass) defines an `onRender` method, call it
    if(this.onRender) this.onRender();

    //...other view code
  }
}

app.Views.childView = kf.Ui.ModalView.extend({
  onRender: function() {
    //your custom code here
  }
});

app.Views.childView = kf.Ui.ModalView.extend({
  render: function() {
    //your custom code here

    //call the base class `render` method
    kf.Ui.ModalView.prototype.render.apply(this, arguments);
  }
});

从超类调用基类方法：

app.Ui.ModalView = Backbone.View.extend({
  render: function() {
    //if this instance (superclass) defines an `onRender` method, call it
    if(this.onRender) this.onRender();

    //...other view code
  }
}

app.Views.childView = kf.Ui.ModalView.extend({
  onRender: function() {
    //your custom code here
  }
});

app.Views.childView = kf.Ui.ModalView.extend({
  render: function() {
    //your custom code here

    //call the base class `render` method
    kf.Ui.ModalView.prototype.render.apply(this, arguments);
  }
});

---

@尼可什，哎呀，修好了。问题是我有时打字比我想象的快。谢谢。你也可以使用主干网访问父类的方式：

this.construtor.\uuuu super\uuuu

@Loamhoof似乎不推荐使用

\uuuu super\uuuu

：（我在阅读时发现）