记住bash变量以再次运行脚本

我试图测试帐户是否被锁定，使用值“1”设置锁定，如果不允许用户登录。（这只是一个学习bash的愚蠢脚本，不是真正的登录，所以忽略任何安全缺陷！）

尝试3次失败后，应将标志设置为1，然后退出脚本。但是，当第二次运行脚本时，它会再次将其设置为默认值0，而不是由于该标志而无法运行

我怀疑问题是由于我将标志变量默认为0，以避免未初始化变量的错误，但我不知道如何“记住”脚本运行的每个实例的变量都设置为1

let x=0
let attempts=0
let PinCode=1234

#checks if locked, default variable value set to 0 (so it is initiated even if first time running script)
if [ ${locked:-0} -eq 1 ]

then
        echo "You are locked out of your account."
else

#runs if unlocked, until third attempt or successful entry
until [ $attempts -eq 3 -o $PinCode -eq $x ]
  do
        echo "Enter your PIN number"
        read x
        if [ $x -eq $PinCode ]

                then
                        echo "Welcome $USER you have correctly entered your PIN. You are connecting from $SSH_CLIENT at $HOSTNAME."

                else
                        let attempts=attempts+1
                        echo -e "Incorrect PIN number"
                        echo -e "\nYou have entered your pin number incorrectly $attempts times. At 3 failures you will be locked out of your
account!"

#locks account on third attempt
                        if [ $attempts -eq 3 ]
                                then let locked=1
                                fi
        fi

  done

fi

exit 0

---

非常感谢您的帮助

从终端启动脚本会使脚本从终端继承环境变量。该脚本中设置的任何环境变量仅在同一脚本的执行期间有效。一旦退出，环境变量就会消失

---

您必须使用其他东西，例如文件，来跟踪脚本多次执行期间的更改。

我使用名为account.locked的文件作为我的标志，使用“touch”创建它，并使用if[-f filename]检查它是否存在，从而修复了它

let x=0
let attempts=0
let PinCode=1234

#checks if locked by searching for flag file
if [ -f locked.account ]
then
        echo "You are locked out of your account."
else

#runs if unlocked, until third attempt or successful entry
until [ $attempts -eq 3 -o $PinCode -eq $x ]
  do
        echo "Enter your PIN number"
        read x
        if [ $x -eq $PinCode ]

                then
                        echo "Welcome $USER you have correctly entered your PIN. You are connecting from $SSH_CLIENT at $HOSTNAME."

                else
                        let attempts=attempts+1
                        echo -e "Incorrect PIN number"
                        echo -e "\nYou have entered your pin number incorrectly $attempts times. At 3 failures you will be locked out of your
account!"

#locks account on third attempt by creating a flag file as a type of global variable replacement
                        if [ $attempts -eq 3 ]
                                then touch locked.account
                                echo "You are locked out of your account."
                                fi
        fi

  done

fi

exit 0