Batch file 在批处理文件中使用echo在单行中合并输出

我想修改下面的脚本，给我一个类似的输出

Number of processes on machine1 are 1

Number of processes on machine2 are 3

Number of processes on machine3 are 7

Number of processes on machine4 are 2

有人能帮忙吗

===============================

@echo off
setlocal enabledelayedexpansion

pushd "%~dp0"

echo %date% %time% 

TASKLIST /S machine1 | grep -c "process" 
TASKLIST /S machine2 | grep -c "process" 
TASKLIST /S machine3 | grep -c "process" 
TASKLIST /S machine4 | grep -c "process" 

---

=====================================

您可以使用filter if IMAGENAME命令为您提供必要的处理。

@echo off
setlocal enabledelayedexpansion

pushd "%~dp0"

echo %date% %time% 

TASKLIST /S machine1 | grep -c "process" 
TASKLIST /S machine2 | grep -c "process" 
TASKLIST /S machine3 | grep -c "process" 
TASKLIST /S machine4 | grep -c "process" 

我使用for命令是因为IMAGENAME的输出行为奇怪…它总是显示在行的开头

@echo off 
set compName1=machine1
for /f %%a in ('tasklist /NH /FO CSV /FI "IMAGENAME eq process" ^| find /C /V ""') do (
    echo Number of processes on %compName1% are %%a
)

---

你在windows下有grep吗？请编辑你的代码以确保可读性。例如，将任何代码缩进四个空格。然后，它以灰色突出显示。