Batch file 如果段落包含某些单词，则批处理文件以删除段落

我需要从.txt文件中删除一个段落，但前提是它包含字符串“Type:sequence”。每个段落之间有两行新行，一行“^**”，还有两行新行。我发现了很多关于如何删除包含某个单词的行的信息，但没有关于段落的信息

如果你不怕正则表达式，你可以用它来解决这个问题

你的规格有点不清楚。根据我对您的布局的理解，我认为以下示例文本中只应保留第2、6和8段：

test.txt

This is paragraph 1 that should be deleted
xxxx Type: Certain xxxx
End of paragraph 1

^**

This is paragraph 2 that should be preserved
End of paragraph 2

^**

This is paragraph 3 Type:
Certain That should be deleted
End of paragraph 3

^**

This is paragraph 4
Type: Certain That should be deleted
End of paragraph 4

^**

Type: Certain

^**

This is paragrpah 6 that should be preserved
End of paragraph 6

^**

This is paragraph 7 that should be deleted
Type: Certain. End of paragraph 7

^**

This is paragraph 8 that should be preserved

^**

This is paragraph 9 that should be deleted
Type: Certain

这里有一个使用JREPL.BAT的解决方案

通过分别更改

p

和

d

的定义，可以修改段落分隔符和删除触发器的正则表达式搜索

@echo off
setlocal
set "p=\r?\n\r?\n\^\*\*\r?\n\r?\n"  %= Paragraph delimiter =%
set "d=\bType:\s+Certain\b"         %= Text that indicates deletion =%

set "find=(%p%)?(?:[\s\S](?!%p%))*%d%[\s\S]*?(?:(%p%)|(?![\s\S]))"
set "repl=$txt=($1&&$2)?$1:''"

call jrepl find repl /m /v /jq /f test.txt /o -

这是删除段落后的文件：

This is paragraph 2 that should be preserved
End of paragraph 2

^**

This is paragrpah 6 that should be preserved
End of paragraph 6

^**

This is paragraph 8 that should be preserved

---

类型的可能性：第一段或最后一段中的某些

使问题有点复杂。

欢迎使用！请编辑您的问题，并提供一些代码样本。您的问题离题（因为您只是请求代码）且不清楚（您如何定义“段落？”。请阅读并学习！