Batch file dos命令将文件名和扩展名转换为变量

我需要将文件x.dtsx从位置a复制到位置b

如果b中已经存在x.dtsx，那么我需要将x.dtsx重命名为x_Standby.dtsx，然后在将x.dtsx副本重命名为b之后

我当前的代码如下所示：

if exists %1 rename %1 %(should be 1_standy.extension)
xcopy %1 %2

if exist %2\%~nx1 ren %2\%~nx1 %~n1_standby%~x1

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如果使用命令处理器扩展（Windows 2000及更高版本的默认设置），则可以使用以下可选语法：

%~1         - expands %1 removing any surrounding quotes (")
%~f1        - expands %1 to a fully qualified path name
%~d1        - expands %1 to a drive letter only
%~p1        - expands %1 to a path only
%~n1        - expands %1 to a file name only
%~x1        - expands %1 to a file extension only
%~s1        - expanded path contains short names only
%~a1        - expands %1 to file attributes
%~t1        - expands %1 to date/time of file
%~z1        - expands %1 to size of file

可以组合修改器以获得复合结果：

%~dp1       - expands %1 to a drive letter and path only
%~nx1       - expands %1 to a file name and extension only

因此，您的命令将如下所示：

if exists %1 rename %1 %(should be 1_standy.extension)
xcopy %1 %2

if exist %2\%~nx1 ren %2\%~nx1 %~n1_standby%~x1

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非常感谢Neil Aweome，我重复一遍：DOS不是CMD，而且

[batch processing]neq[batch=file]