Button &引用;“下一步”;键不';行不通
我有两个文本文件。在第一个字段中,我在keybord上设置了“Next”按钮,但按钮“Done”在第二个字段中起作用。我写了这段代码Button &引用;“下一步”;键不';行不通,button,ios6,sdk,keyboard,uitextfield,Button,Ios6,Sdk,Keyboard,Uitextfield,我有两个文本文件。在第一个字段中,我在keybord上设置了“Next”按钮,但按钮“Done”在第二个字段中起作用。我写了这段代码 - (BOOL)textFieldShouldReturn:(UITextField *)theTextField { if (theTextField == self.loginField) { [theTextField resignFirstResponder]; } else if (theTextField == self.passField)
- (BOOL)textFieldShouldReturn:(UITextField *)theTextField {
if (theTextField == self.loginField) {
[theTextField resignFirstResponder];
} else if (theTextField == self.passField) {
[self.passField becomeFirstResponder];
}
return YES;
}
也许我在某些方面错了。是否连接xib中的文本字段委托?导入UITEXTFIELDEGRADE。
-(BOOL)textFieldShouldReturn:(UITextField *)textField
{
if(textField == self.loginField)
{
[self.passField becomeFirstResponder];
}
else if(textField == self.passField)
{
[textField resignFirstResponder];
}
return YES;
}
In xib, select LoginField - Return key set as "Next", Select PassField - Return key as "Done"/"Next".