C do while循环中的字符串

改变

到

及

到

---

另外，不要忘记包括

string.h

您正在比较指针，而不是它们指向的字符串。看一看。另外，如果你在后面写两个字符串文字，它们将被编译器合并。那么，你有没有在调试器中检查过你的代码，检查过变量等等。？这是第一件要做的事。还可以阅读C中的字符串比较，因为[str1！=“END”]不起作用。这些是指针，谢谢。我做了这些改变，我仍然把它转换成拉丁语，而不仅仅是结束节目。我应该在那里的某个地方添加一个中断吗？只要添加

if（strcmp（str，“END”）==0）中断

在

scanf

之后，使用一个无限循环，类似于

for（；；）

或

while（1）

// PigLatinFinal.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include <stdio.h>

void Heading (void)
{
    printf("************************************************************\n");
    printf("*                        Pig Latin                         *\n");
    printf("*                                                          *\n");
    printf("*                                                          *\n");
    printf("*                     Welcome                              *\n");
    printf("*                                                          *\n");
    printf("* In this program, the user will enter a word in English   *\n");
    printf("* The program will then return the word in Pig Latin.      *\n");
    printf("* The word cannot be longer than 7 letters.  You can       *\n");
    printf("* translate as many words as you wish. Enter 'END' without *\n");
    printf("* the quotation marks to end the program. 'END is case     *\n");
    printf("* sensitive                                                *\n");
    printf("*                                                          *\n");
    printf("************************************************************\n");
    printf("\n\n\n\n");
}

int main(void)
{
    Heading();
    char str1[20];
    int i =0;
    do
        {

        int count =0;
        do
            {          
            printf("Enter a word in English for the program to return in Pig Latin: ");
            scanf("%s", str1);
            while(str1[count] != '\0')
            ++count;
            if (count>7)
                {
                printf("\n\nInvalid Entry. Please enter a word with no more than 7 letters\n\n");
                count=0;
                }
            }while (count>7);//loop to perform if invalid word is entered

         //while (count<7)
         //
        printf("\n%s in Pig Latin: ",str1);
        for (i=1;str1[i];++i)
            {
            printf("%c",str1[i]);
            }
        printf("%c",str1[0]);
        printf("ay");
        printf("\n\n\n");
         //}


    }while(str1!= "END"); 

return 0;
    }

}while (count>7);//loop to perform if invalid word is entered

}while (count==0);//loop to perform if invalid word is entered

}while(str1!= "END");

}while(strcmp(str1,"END")!=0);