C 我应该在条件语句中更改什么以生成正确的三角形分类?
我想让用户输入任意三个值来表示三角形边的尺寸。代码中的条件语句将对边是否构成三角形进行分类。如果它确实构成三角形,它将显示三角形是不等边三角形还是直角三角形,或者两者都是C 我应该在条件语句中更改什么以生成正确的三角形分类?,c,ubuntu-16.04,C,Ubuntu 16.04,我想让用户输入任意三个值来表示三角形边的尺寸。代码中的条件语句将对边是否构成三角形进行分类。如果它确实构成三角形,它将显示三角形是不等边三角形还是直角三角形,或者两者都是 #include <stdio.h> int main(void) { //Declare the variables for the sides of the triangle float a; //first side float b; //second side float c; /
#include <stdio.h>
int main(void)
{
//Declare the variables for the sides of the triangle
float a; //first side
float b; //second side
float c; //third side
float scalene; //check for scalene
float right; //check for right
float ans; //check if sides are a triangle
float rep; //check if user wants to continue after the sides are not a
triangle
//Get user inputs for the sides of the triangle
printf("Input the first side of the triangle: ");
scanf("%f", &a);
printf("Input the side for the second side of the triangle: ");
scanf("%f", &b);
printf("Input the last side of the triangle: ");
scanf("%f", &c);
//Conditional statements:
//Determine if the sides make up a triangle
>if ((a+b)<c || (b+c)<a || (a+c)<b)
>{
ans=0;
}
else
{
ans=1;
}
//If the sides make up a triangle, is the triangle scalene? If scalene,
//each side is unique to the others
for (ans=1;ans<3;ans++)
{
if (a==b || a==c || b==c)
{
scalene=0;
>}
else
{
scalene=1;
}
//if the sides make a right triangle, they would satisfy one of the
//following Pythagorean theorem
if ((a*a+b*b)==(c*c) || (b*b+c*c)==(a*a) || (a*a+c*c)==(b*b))
{
right=1;
}
else
{
right=0;
}
for (ans=0;ans<2;ans++)
>{
printf("Your sides do not make a triangle. Enter 1 if you would like to
input new values. Enter any other number to finish: \n");
scanf("%f", &rep);
}
if (rep==1) //repeat the steps again
{
printf("Input the first side of the triangle: ");
scanf("%f", &a);
printf("Input the side for the second side of the triangle: ");
scanf("%f", &b);
printf("Input the last side of the triangle: ");
scanf("%f", &c);
>}
else
{
printf("Thank you for using Triangle Check. Have a nice day!");
return 0;
}
}
//Display the results to the user
if (scalene==1 && right==1)
{
printf("Your triangle is both a scalene and right!");
return 0;
}
else if (scalene==0 && right==1)
{
printf("Based on your sides, it is a right triangle!");
return 0;
}
else if (scalene==1 && right==0)
{
printf("Based on your sides, it is a right triangle!");
return 0;
}
else
{
printf("Your triangle is neither right or scalene.");
return 0;
}
return 0;
}
#包括
内部主(空)
{
//声明三角形边的变量
浮动a;//第一面
浮点b;//第二个边
浮点c;//第三方
float scalene;//检查是否存在scalene
向右浮动;//检查是否向右浮动
float ans;//检查边是否为三角形
float rep;//检查用户是否希望在侧边未对齐后继续
三角形
//获取三角形边的用户输入
printf(“输入三角形的第一条边:”);
scanf(“%f”、&a);
printf(“输入三角形第二条边的边:”);
scanf(“%f”和“b”);
printf(“输入三角形的最后一边:”);
scanf(“%f”、&c);
//条件语句:
//确定边是否构成三角形
>如果((a+b)您的逻辑混乱,因此您感到困惑。摆脱ans
-您不需要它。构建您的程序以立即响应内容。摆脱您不需要的循环。(此程序根本不需要任何循环。)
例如,当检查是否为三角形时,请检查,如果失败,请退出
然后继续进行下一个测试
Flaggy程序(您使用的ans
、scalene
、right
等只报告真值的程序)对您没有帮助。请避免使用技巧
祝你好运!将所有信息放入html注释中,这样它们就看不见了,这真的是一个毫无帮助的想法。它已经让你投了反对票。赶快采取行动,否则你的理解力不足将使你无法得到一个好答案。“你得到的实际结果是什么?”展示出来,然后解释一下。
if ((a+b)<c || (b+c)<a || (a+c)<b)
{
puts( "Alas, your sides to not make a triangle." );
return 1;
}
if (a != b && b != c)
{
puts( "The triangle is SCALENE." );
}