C 取消引用指向不完整类型抽象数据类型的指针

我有以下代码部分：

字典.h

#ifndef _DICTIONARY_H
#define _DICTIONARY_H

typedef struct _dict_t dict_t;
typedef dict_t *Dictionary;

Dictionary dict_new(void);
(...)

字典.c

#include "dictionary.h"
struct _dict_t {
    unsigned int size;
    char **data;
};

Dictionary dict_new(void){
    Dictionary dict = NULL;
    dict = calloc(1, sizeof(struct _dict_t));
    dict->data = calloc(1, sizeof(char));
    dict->size = 0;
    return (dict);
}

#include "dictionary.h"
Dictionary main_dict; // global dictionary
Dictionary ignored;   // Yes, i know its horrible

int is_known(char *word){
    int i;
    for (i = 0; i < main_dict->size; ++i)  {
        if (strcmp(main_dict->data[i], word) == 0)
            return 1;
    }

    for (i = 0; i < ignored->size; ++i){
        if (strcmp(ignored->data[i], word) == 0)
            return 1;
    }
    return 0;
}

int main(){
    (...)
}

main.c

#include "dictionary.h"
struct _dict_t {
    unsigned int size;
    char **data;
};

Dictionary dict_new(void){
    Dictionary dict = NULL;
    dict = calloc(1, sizeof(struct _dict_t));
    dict->data = calloc(1, sizeof(char));
    dict->size = 0;
    return (dict);
}

#include "dictionary.h"
Dictionary main_dict; // global dictionary
Dictionary ignored;   // Yes, i know its horrible

int is_known(char *word){
    int i;
    for (i = 0; i < main_dict->size; ++i)  {
        if (strcmp(main_dict->data[i], word) == 0)
            return 1;
    }

    for (i = 0; i < ignored->size; ++i){
        if (strcmp(ignored->data[i], word) == 0)
            return 1;
    }
    return 0;
}

int main(){
    (...)
}

---

我找不到错误。发生了什么？

当类型不完整时，编译器不知道该类型的实例中有什么。您需要提供类型的定义，然后才能取消引用它。

您正在取消引用指向不完整类型的指针。哪个词或表达不清楚？你用谷歌搜索过吗？

typedef

一个简单的指针不是一个好主意，因为实现缺少

*

，否则代码很难被理解。