C中的枚举是有符号的还是无符号的?
枚举在C中是有符号的还是无符号的?我正在使用Gcc编译我的程序,结果是2个枚举值,如下代码所示:C中的枚举是有符号的还是无符号的?,c,enums,unsigned,C,Enums,Unsigned,枚举在C中是有符号的还是无符号的?我正在使用Gcc编译我的程序,结果是2个枚举值,如下代码所示: typedef enum test_e { zero, one, two, three, }test_t; void compare_func(test_t var) { printf("\n [1] my number is %d \n", var); if ( var > 0) printf(" %d > 0 \n"
typedef enum test_e
{
zero,
one,
two,
three,
}test_t;
void compare_func(test_t var)
{
printf("\n [1] my number is %d \n", var);
if ( var > 0)
printf(" %d > 0 \n", var);
else if ( var < 0)
printf(" %d < 0 \n", var);
}
typedef enum test_nega_e
{
zero_nega,
one_nega = -1,
two_nega = -2,
three_nega = -3,
}test_nega_t;
void compare_nega_func(test_nega_t var_nega)
{
printf("\n [2] my number_nega is %d \n", var_nega);
if ( 0 < var_nega)
printf(" %d > 0 \n", var_nega);
else if ( 0 > var_nega)
printf(" %d < 0 \n", var_nega);
}
int main (void)
{
test_t my_number;
test_nega_t my_number_nega;
my_number = -1;
compare_func(my_number);
my_number_nega = -1;
compare_nega_func(my_number_nega);
return 0;
}
结果是:
[1] my number is -1
-1 > 0
[2] my number_nega is -1
-1 < 0
那么我的号码是无符号的,我的号码是有符号的?谢谢您不能依赖已签名或未签名的枚举 看 请注意C和C++的枚举是相似的