C 每个未声明的标识符只报告一次?
我正在写一个c程序,涉及孩子和家长之间通过定向管道进行通信 以下是我的部分代码:C 每个未声明的标识符只报告一次?,c,process,pipe,C,Process,Pipe,我正在写一个c程序,涉及孩子和家长之间通过定向管道进行通信 以下是我的部分代码: char writemsg[BUFFER_SIZE] = "Sugar Lover"; char readmsg[BUFFER_SIZE]; char parrecieve[BUFFER_SIZE]; char childrecieve[BUFFER_SIZE+1]; int fd[2]; int fd2[2]; pid_t pid; if (pipe(fd) == -1|| pi
char writemsg[BUFFER_SIZE] = "Sugar Lover";
char readmsg[BUFFER_SIZE];
char parrecieve[BUFFER_SIZE];
char childrecieve[BUFFER_SIZE+1];
int fd[2];
int fd2[2];
pid_t pid;
if (pipe(fd) == -1|| pipe(fd2) == -1) {
printf("Pipe failed");
return 1;
}
pid = fork();
if (pid < 0) { /* error occurred */
printf( "Fork Failed");
return 1;
}
if (pid > 0) { /* parent process */
int i =0;
close(fd[READ_END]);/* close the unused end of the pipe */
while(writemsg[i] !='\0'){
write(fd[WRITE_END],&writemsg[i] , sizeof(char));
i++;
}
close(fd[WRITE_END]);
i = 0;
close(fd2[WRTIE_END]);
while(read(fd2[READ_END], &parrecieve[i], sizeof(char))!=0){
printf("%c", parrecieve[i]);
i++;
}
close(fd2[READ_END]);
}
谁能告诉我为什么?谢谢 只需将
WRTIE\u END
重命名为WRITE\u END
更仔细地阅读错误消息,并尝试理解它们。描述性标题FTW!赞成。。我已经编了几个小时的程序,现在太累了,我自己都找不到打字错误:(谢谢tho!@NobWong:这是真的:)你的经验越多,有些事情就越明显:)
close(fd2[WRTIE_END]);