用C语言将大块二进制文件转换成文本

我有一个项目，其中我应该通过getchar（）函数接收一个文件，并将其中的二进制字符转换为文本

这是我的代码，它一次只能为一个生成正确的ASCII码。我不知道如何读入整个文本文件的二进制文件并将其转换：

#include <stdio.h>
#include <string.h>

typedef unsigned char byte;
typedef unsigned int uint;

int strbin_to_dec(const char *);

int main(void) {



char * wbin = "01001001";
  int c = 0;

  printf("%s to ascii %d.\n", wbin, strbin_to_dec(wbin));
  printf("The character is %c", strbin_to_dec(wbin));
  return 0;
}

int strbin_to_dec(const char * str) {
  uint result = 0;
  for (int i = strlen(str) - 1, j = 0; i >= 0; i--, j++) {
    byte k = str[i] - '0';
    k <<= j;
    result += k;
  }
  return result;
}

我要翻译的文件如下所示：

0010001001001000011011110111011100100000011011110110011001110100011001010110111000100000011010000110000101110110011001010010000001001001001000000111001101100001011010010110010000100000011101000110111100100000011110010110111101110101
011101000110100001100001011101000010000001110111011010000110010101101110001000000111100101101111011101010010000001101000011000010111011001100101001000000110010101101100011010010110110101101001011011100110000101110100011001010110010000100000011101000110100001100101001000000110100101101101011100000110111101110011011100110110100101100010011011000110010100101100
01110111011010000110000101110100011001010111011001100101011100100010000001110010011001010110110101100001011010010110111001110011001011000010000001101000011011110111011101100101011101100110010101110010001000000110100101101101011100000111001001101111011000100110000101100010011011000110010100101100
01101101011101010111001101110100001000000110001001100101001000000111010001101000011001010010000001110100011100100111010101110100011010000011111100100010
0010110101010011011010010111001000100000010000010111001001110100011010000111010101110010001000000100001101101111011011100110000101101110001000000100010001101111011110010110110001100101001011000010000001010100011010000110010100100000010100110110100101100111011011100010000001001111011001100010000001000110011011110111010101110010

---

读入文件中的所有输入，并一次向转换器函数传递8个字符以返回一个字符。每个字符是8位，文件中的每个字符代表1位

char string_to_character(char * in)
{
  char ret = 0;
  int i;
  for(i = 7; i >= 0; i--)
    if(in[i] == '1')
      ret += 1 << (7 - i);

  return ret;
}

char字符串到字符（char*in）
{
char-ret=0；
int i；
对于（i=7；i>=0；i--）
如果（在[i]=“1”中）
ret+=1=不>

用于循环

假设您将整个文件作为一个长字符串

int num_chars = (sizeof(input) / sizeof(char)) / 8;
int i;
char output[num_chars + 1];
for(i = 0; i < num_chars; i++)
   output[i] = string_to_character(input + (i * 8));

printf("%s", output);

int num_chars=（sizeof（input）/sizeof（char））/8；
int i；
字符输出[num_chars+1]；
对于（i=0；i

这是我从节目中得到的结果

“我有多少次对你说过，当你消除了不可能的事情，剩下的无论多么不可能，都一定是真相？”-亚瑟爵士
柯南·道尔，四的标志

编辑：left bitshift vs pow
这是我做的一个函数！我不知道您是否使用该文件作为执行参数，如：./text.exe-f binary.txt！但我不向程序添加条目！我自己定义了该文件

我已经创建了一个函数来写入文件，但是如果你想使用像./text.exe-f binary.txt>translatedfile.txt这样的命令，你可以简单地删除函数write_to_file！不要忘记删除你不想要的打印，因为参数“>”会打印所有内容

代码：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void binary_to_char(char *str);
void write_to_file(char *text);

int main(void)
{

    printf("Getting line from file\n");

    FILE *file;
    char *line = NULL;
    size_t len = 0;
    ssize_t stringLength;

    file = fopen("binary.txt", "r");
    if (file == NULL)
    {
        fprintf(stderr, "[ERROR]: cannot open file -- binary.txt");
        perror("");
        exit(1);
    }

    while ((stringLength = getline(&line, &len, file)) != -1)
    {
        printf("\n%s", line);
        binary_to_char(line);
    }
    free(line);
    fclose(file);

    return 0;
}

void binary_to_char(char *str)
{
    char binary[9];
    char *text = malloc((strlen(str) + 1) * sizeof(char));
    char c;
    int pos = 0;
    int letter_pos = 0;
    printf("\nConverting into characters\n");
    for (size_t j = 0; j < strlen(str) / 8; j++)
    {
        for (int i = 0; i < 8; i++)
        {
            binary[i] = str[pos];
            pos++;
        }
        c = strtol(binary, 0, 2);
        text[letter_pos] = c;
        letter_pos++;
    }
    printf("\n%s\n", text);
    write_to_file(text);
    free(text);
}

void write_to_file(char *text)
{
    printf("\nContent saved to translatedfile.txt\n");
    FILE *fp;

    fp = fopen("translatedfile.txt", "w+");
    fprintf(fp, "%s", text);

    fclose(fp);
}

001000100100100001101111011101110010000001101111011001100111010001100101011011100010000001101000011000010111011001100101001000000100100100100000011100110110000101101001011001000010000001110100011011110010000001111001011011110111010101110100011010000110000101110100001000000111011101101000011001010110111000100000011110010110111101110101001000000110100001100001011101100110010100100000011001010110110001101001011011010110100101101110011000010111010001100101011001000010000001110100011010000110010100100000011010010110110101110000011011110111001101110011011010010110001001101100011001010010110001110111011010000110000101110100011001010111011001100101011100100010000001110010011001010110110101100001011010010110111001110011001011000010000001101000011011110111011101100101011101100110010101110010001000000110100101101101011100000111001001101111011000100110000101100010011011000110010100101100011011010111010101110011011101000010000001100010011001010010000001110100011010000110010100100000011101000111001001110101011101000110100000111111001000100010110101010011011010010111001000100000010000010111001001110100011010000111010101110010001000000100001101101111011011100110000101101110001000000100010001101111011110010110110001100101001011000010000001010100011010000110010100100000010100110110100101100111011011100010000001001111011001100010000001000110011011110111010101110010

这是一项简单的任务，只需使用位移位即可完成。此外，为了提高性能，下面使用了
fread
，而不是使用
getchar

此实现使用最小的RAM（不使用malloc）、无慢速字符串解析或数学函数，如
strlen
、
strtol
或
pow
，并且可以处理无限大小/长度的任何流，包括不是8字节倍数的截断流

用法：
/a.outout.txt

#包括
int main（int argc，char*argv[]）
{
无符号字符字节=0；
整数位=0；
对于（；；）
{
字符缓冲区[1024]；
int len=fread（缓冲区，1，sizeof（缓冲区），stdin）；
//如果出现读取错误或EOF，请停止
如果（len）是您的问题“如何从文件中读取字符”？事实上，看起来你甚至不需要从一个文件中读取，而是从一个重定向的
stdin
中读取，为什么不使用循环？但你想让它只翻译一个字符或整个字符串？@EugeneSh。如果我正确地跟踪了你，那么这就是我正在做的，但我现在不知道如何翻译整个内容。这与读取fi不同le in，从我使用FILE对象可以看出。我是C新手，如果我的术语不正确，我很抱歉。@GonçaloBastos我需要翻译我文章底部的整个文本块，这是一本书中的引用，但我不知道如何循环二进制文件并获取我需要提供给函数的内容。这个答案是e非常差。它不仅需要先读取整个输入（对于读取
stdin
无效，并且限制输入大小），它还使用
malloc
、
strlen
和
strol
来完成简单的位移位操作。@Geoffrey好的，我只是想帮忙！这不仅需要读取整个文件，还需要使用
pow
来完成简单的
或
可以完成的操作，左移位简直是疯了。@Geoffrey Fair，左移效率更高。但问题需要读取整个文件，这是不可避免的。需要读取整个文件。是的，但不需要将整个文件缓冲到RAM中，也不需要按照OP的要求读取
stdin
。输入的长度不是确定的，而且不需要ld是无限的。看我的答案。它肯定会运行得慢得多，因为磁盘访问时间比ram访问慢几百倍。说什么？无论如何，你都必须从磁盘上读取文件。这是一个从stdin读取到malloc'ed-region，从二进制转换到malloc'ed-region，还是从二进制转换的问题f-of-stdin。我不认为后者不是一场胜利。另请参见和。为什么你必须反复阅读文件？我认为一次传球就可以了。
001000100100100001101111011101110010000001101111011001100111010001100101011011100010000001101000011000010111011001100101001000000100100100100000011100110110000101101001011001000010000001110100011011110010000001111001011011110111010101110100011010000110000101110100001000000111011101101000011001010110111000100000011110010110111101110101001000000110100001100001011101100110010100100000011001010110110001101001011011010110100101101110011000010111010001100101011001000010000001110100011010000110010100100000011010010110110101110000011011110111001101110011011010010110001001101100011001010010110001110111011010000110000101110100011001010111011001100101011100100010000001110010011001010110110101100001011010010110111001110011001011000010000001101000011011110111011101100101011101100110010101110010001000000110100101101101011100000111001001101111011000100110000101100010011011000110010100101100011011010111010101110011011101000010000001100010011001010010000001110100011010000110010100100000011101000111001001110101011101000110100000111111001000100010110101010011011010010111001000100000010000010111001001110100011010000111010101110010001000000100001101101111011011100110000101101110001000000100010001101111011110010110110001100101001011000010000001010100011010000110010100100000010100110110100101100111011011100010000001001111011001100010000001000110011011110111010101110010

0010001001001000011011110111011100100000011011110110011001110100011001010110111000100000011010000110000101110110011001010010000001001001001000000111001101100001011010010110010000100000011101000110111100100000011110010110111101110101
011101000110100001100001011101000010000001110111011010000110010101101110001000000111100101101111011101010010000001101000011000010111011001100101001000000110010101101100011010010110110101101001011011100110000101110100011001010110010000100000011101000110100001100101001000000110100101101101011100000110111101110011011100110110100101100010011011000110010100101100
01110111011010000110000101110100011001010111011001100101011100100010000001110010011001010110110101100001011010010110111001110011001011000010000001101000011011110111011101100101011101100110010101110010001000000110100101101101011100000111001001101111011000100110000101100010011011000110010100101100
01101101011101010111001101110100001000000110001001100101001000000111010001101000011001010010000001110100011100100111010101110100011010000011111100100010
0010110101010011011010010111001000100000010000010111001001110100011010000111010101110010001000000100001101101111011011100110000101101110001000000100010001101111011110010110110001100101001011000010000001010100011010000110010100100000010100110110100101100111011011100010000001001111011001100010000001000110011011110111010101110010

"How often have I said to youthat when you have eliminated the impossible,whatever remains, however improbable,must be the truth?"-Sir Arthur Conan Doyle, The Sign Of Four