Clang 无效值'；边缘'；在'；fsantize coverage=edge'；使用LLVM LibFuzzer时

我现在正在用libfuzzer做一些工作，但是当我用官方的玩具例子做的时候。运行此命令时：

clang++ -fsanitize=address -fsanitize-coverage=edge test-fuzzer.cc Fuzzer*.o

发生了一个错误

clang: error: invalid value 'edge' in 'fsanitize-coverage=edge'

似乎clang支持这个论点，但我想知道我如何才能看到支持的价值。。。

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我用unbuntu14.04安装了apt get的llvm 3.6…

如2015年5月所述，更改了

fsanizize coverage=

标志的语法。此位与您特别相关：

Original semantics of -fsanitize-coverage flag is preserved:
  * -fsanitize-coverage=0 disables the coverage
  * -fsanitize-coverage=1 is a synonym for -fsanitize-coverage=func
  * -fsanitize-coverage=2 is a synonym for -fsanitize-coverage=bb
  * -fsanitize-coverage=3 is a synonym for -fsanitize-coverage=edge
  * -fsanitize-coverage=4 is a synonym for -fsanitize-coverage=edge,indirect-calls

因此，您可以尝试

-fsanizize coverage=3