Cocoa touch iphone上的facebook发布POST API：未正确发布

我正在尝试使用facebook发布API链接，如下所示

它成功发布了，但不像我预期的那样
没有标题、名称、描述、链接等
它显示为

我可以通过这个参数得到这种类型的结果

NSMutableDictionary* params = [NSMutableDictionary dictionaryWithObjectsAndKeys:
                                         @"Test test", @"message",
                                         privacyJSONStr, @"privacy",
                                         nil];

错误是什么？我们如何发布所有参数

NSMutableDictionary* params = [NSMutableDictionary dictionaryWithObjectsAndKeys:
                                         @"Test test", @"message",
                                         privacyJSONStr, @"privacy",
                                         nil];

---

阿米特·巴坦试试这个。。它对我有用

- (IBAction )publishStream{

    SBJSON *jsonWriter = [[SBJSON new] autorelease];

    NSDictionary* actionLinks = [NSArray arrayWithObjects:[NSDictionary dictionaryWithObjectsAndKeys:
                                                           @"Posting From",@"text",@"http://www.google.com/",@"href", nil], nil];

    NSString *actionLinksStr = [jsonWriter stringWithObject:actionLinks];

    NSLog(@"Action Link String : %@", actionLinksStr);

    NSDictionary* attachment = [NSDictionary dictionaryWithObjectsAndKeys:
                                @"Feed Name", @"name",
                                @"Feed Caption is here", @"caption",
                                @"Feed Description is here", @"description",
                                @"http://www.google.com/", @"href", nil];


    NSString *attachmentStr = [jsonWriter stringWithObject:attachment];

    NSLog(@"Attachment String : %@", attachmentStr);

    NSMutableDictionary* params = [NSMutableDictionary dictionaryWithObjectsAndKeys:
                                   @"Share on Facebook",  @"user_message_prompt",
                                   actionLinksStr, @"action_links",
                                   attachmentStr, @"attachment",
                                   nil];


    [facebook dialog:@"facebook.Stream.publish"
            andParams:params
          andDelegate:self];

}

---

你确定privacyJSONStr！=nil？privacyJSONStr没有空值。它在第二种情况下很好好我会试试。。。。为什么我们要给链接两次<代码>http://www.google.com 作为动作链接和附件中的href