C++ 全局数组的多定义错误

我正在尝试编译我的C++代码，我继续获得错误：

/tmp/ccEsZppG.o:(.bss+0x0): multiple definition of `mailboxes'
/tmp/ccEZq43v.o:(.bss+0x0): first defined here
/tmp/ccEsZppG.o:(.bss+0xc0): multiple definition of `threads'
/tmp/ccEZq43v.o:(.bss+0xc0): first defined here
/tmp/ccEsZppG.o:(.bss+0x120): multiple definition of `semaphores'
/tmp/ccEZq43v.o:(.bss+0x120): first defined here
collect2: error: ld returned 1 exit status

这是我的密码：

addem.cpp

#include <stdio.h>
#include <iostream>
#include <stdlib.h>
#include <semaphore.h>
#include <pthread.h>
#include "mailbox.h"


using namespace std;

void *sumUp(void *arg);

int main(int argc, char *argv[]) {

  int numThreads, minThreads, maxInt, minInt;
  if (argc < 3) {
    cout << "Error: Need three arguments" << endl;
    return 1;
  }

  numThreads = atoi(argv[1]);
  maxInt = atoi(argv[2]);
  minThreads = 1;
  minInt = 1;

  if (numThreads < 1) {
    cout << "Cannot work with less than one thread\n"
         << "It's okay but do better next time!\n"
         << "We'll work with 1 thread this time.\n";
    numThreads = minThreads;
  } else if (numThreads > MAXTHREAD) {
    cout << "Sorry, the max for threads is 10.\n"
         << "We'll work with 10 threads this time.\n";
    numThreads = MAXTHREAD;
  }

  if (maxInt < 1) {
    cout << "What do you want me to do? I can't count backwards!\n"
         << "I can barely count forwards! Let's make the max number\n"
         << "be 1 to save time\n";
    maxInt = minInt;
  }

  struct msg outgoingMail[numThreads];
  int divider = maxInt / numThreads;
  int count = 1;

  //initialize arrays (mailboxes, semaphores)
  for (int i = 0; i < numThreads; i++) {
    sem_init(&semaphores[i], 0, 1);
    outgoingMail[i].iSender = 0;
    outgoingMail[i].type = RANGE;
    outgoingMail[i].value1 = count;
    count = count + divider;

    if (i = numThreads - 1) {
      outgoingMail[i].value2 = maxInt;
    } else {
      outgoingMail[i].value2 = count;
    }
  }

  for (int message = 0; message < numThreads; message++) {
    SendMsg(message+1, outgoingMail[message]);
  }
  int thread;
  for (thread = 0; thread <= numThreads; thread++) {
    pthread_create(&threads[thread], NULL, &sumUp, (void *)(intptr_t)(thread+1));
  }

  struct msg incomingMsg;
  int total = 0;
  for (thread = 0; thread < numThreads; thread++) {
    RecvMsg(0, incomingMsg);

    total = total + incomingMsg.value1;
  }

  cout << "The total for 1 to " << maxInt << " using "
       << numThreads << " threads is " << total << endl;

  return 0;
}

void *sumUp(void *arg) {

  int index,total;

  index = (intptr_t)arg;
  struct msg message;

  RecvMsg(index, message);

  message.iSender = index;
  message.type = ALLDONE;

  total = 0;
  for (int i = message.value1; i <= message.value2; i++) {
    total += i;
  }
  SendMsg(0, message);
  
  return (void *) 0;
}

我尝试注释掉源代码中的所有函数体，将它们保留为存根函数，同样的错误也会发生。编译该文件的唯一方法是注释掉函数体，然后删除

#include "mailbox.h"

---

来自至少一个文件。我觉得这与我如何初始化阵列有关？但是我无法找到解决方法。

使用

extern

在头文件中声明这些数组，并在.cpp文件中添加定义。哪个.cpp文件？它们都可以访问阵列选择其中一个（并且只有一个），这无关紧要。如果您觉得在其中一个中定义它们是错误的，请创建另一个，并在那里定义您的数组。这很有效！非常感谢你抽出时间来帮助我，你让我高兴极了！

#ifndef MAILBOX_H_
#define MAILBOX_H_

#define RANGE 1
#define ALLDONE 2

#define MAXTHREAD 10


#include <semaphore.h>
#include <pthread.h>

struct msg {
  int iSender; /* sender of the message (0 .. numThreads)*/
  int type; /* its type */
  int value1; /* first value */
  int value2; /* second value */
};

struct msg mailboxes[MAXTHREAD + 1];
pthread_t threads[MAXTHREAD + 1];
sem_t semaphores[MAXTHREAD + 1];

int SendMsg(int iTo, struct msg &Msg);
int RecvMsg(int iFrom, struct msg &Msg);
bool safeToCall(int location);


#endif

g++ -o addem addem.cpp mailbox.cpp -lpthread

#include "mailbox.h"