C++ 模板类的非侵入式序列化方法

我使用的是boost序列化，主要是入侵版本。对于模板矩阵类，我希望使用在Visual Studio上工作的，并使用以下代码：

namespace boost 
{
    namespace serialization 
    {

        template<class Archive, int R, int C, class ElementType>
        void serialize(Archive & ar, Matrix<R, C, ElementType> & m, const unsigned int version)
        {
            ar & ...
        }

    } 
}

如果我用一种特殊的形式，比如

namespace boost 
{
    namespace serialization 
    {

        template<class Archive>
        void serialize(Archive & ar, Matrix<3,1,double> & m, const unsigned int version)
        {
            ar & ...
        }

    } 
}

---

在我看来，这似乎是有符号/无符号不匹配。模板函数是用

int

s声明的，但错误表明它试图与模板匹配的对象具有参数

1u

和

3u

。当实例化要序列化的对象时，是否对维度使用无符号值？尝试更改serialize template函数以获取未签名的s，或使用ints实例化矩阵。

如何调用serialize方法？boost调用它，请参阅我的编辑。

namespace boost 
{
    namespace serialization 
    {

        template<class Archive>
        void serialize(Archive & ar, Matrix<3,1,double> & m, const unsigned int version)
        {
            ar & ...
        }

    } 
}

/[myfolder]/lib/BOOST/1_44_0/include/boost/serialization/access.hpp: In static member function 'static void boost::serialization::access::serialize(Archive&, T&, unsigned int) [with Archive = boost::archive::binary_iarchive, T = Matrix<3u, 1u, double>]':
/[myfolder]/lib/BOOST/1_44_0/include/boost/serialization/serialization.hpp:70: instantiated from 'void boost::serialization::serialize(Archive&, T&, unsigned int) [with Archive = boost::archive::binary_iarchive, T = Matrix<3u, 1u, double>]'
/[myfolder]/lib/BOOST/1_44_0/include/boost/serialization/serialization.hpp:129: instantiated from 'void boost::serialization::serialize_adl(Archive&, T&, unsigned int) [with Archive = boost::archive::binary_iarchive, T = Matrix<3u, 1u, double>]'
/[myfolder]/lib/BOOST/1_44_0/include/boost/archive/detail/iserializer.hpp:182: instantiated from 'void boost::archive::detail::iserializer<Archive, T>::load_object_data(boost::archive::detail::basic_iarchive&, void*, unsigned int) const [with Archive = boost::archive::binary_iarchive, T = Matrix<3u, 1u, double>]'