C++ 超载<&书信电报；对于c++；班

我试图为包含对象数组的codeMemSet/code模板重载

>r；
cin>>r2；
cin>>r3；
mset.add（r）；
mset.add（r2）；
mset.add（r3）；
coutr5；
cin>>r6；
mset2.添加（r）；
mset2.add（r2）；
mset2.添加（r3）；
如果（mset==mset2）
cout使用语法
mm1将'mset'添加到'mm1'这里有一个示例，它提供了类似于我假设您想要的行为。您需要扩展类以提供比较

#include <iostream>
#include <vector>
#include <string>
using namespace std;

class Record
{
    friend istream& operator>> (istream& s, Record& r);
    friend ostream& operator<< (ostream& s, Record& r);

public:
    int GetAge(void) const { return m_nAge; }
    const std::string& GetFirstName(void) const { return m_strFirstName; }
    const std::string& GetLastName(void) const { return m_strLastName; }

private:
    int m_nAge;
    string m_strFirstName;
    string m_strLastName;
};

istream& operator>> (istream& s, Record& r)
{
    s >> r.m_nAge;
    s >> r.m_strFirstName;
    s >> r.m_strLastName;
    return s;
}

ostream& operator<< (ostream& s, Record& r)
{
    s << "Individual: " << r.m_strLastName << ", "
        << r.m_strFirstName << " (" << r.m_nAge << " years)" << endl;
    return s;
}

template<class T>
class MemSet : public vector<T>
{
    template<class T1>
    friend ostream& operator<< (ostream& s, MemSet<T1>& m);

    template<class T1>
    friend MemSet<T1>& operator<< (MemSet<T1>& m, T1& t);
};

template<class T>
ostream& operator<< (ostream& s, MemSet<T>& m)
{
    for (typename vector<T>::iterator it = m.begin(); it != m.end(); ++it)
        s << *it;
    return s;
}

template<class T>
MemSet<T>& operator<< (MemSet<T>& m, T& t)
{
    m.push_back(t);
    return m;
}

int main(int argc, char** argv)
{
    MemSet<Record> mset1, mset2;
    MemSet< MemSet<Record> > mm;
    Record temp;

    cin >> temp; mset1.push_back(temp);
    cin >> temp; mset1.push_back(temp);
    cin >> temp; mset1.push_back(temp);

    cin >> temp; mset2.push_back(temp);
    cin >> temp; mset2.push_back(temp);
    cin >> temp; mset2.push_back(temp);

    cout << mset1 << endl;

    mm << mset1;
    mm << mset2;

    cout << mm << endl;

    return 0;
}

#包括
#包括
#包括
使用名称空间std；
课堂记录
{
friend istream&operator>>（istream&s、Record&r）；
friend ostream&operator>（istream&s、Record&r）
{
s>>r.m_ènAge；
s>>r.m_strFirstName；
s>>r.m_strLastName；
返回s；
}
ostream&operatorWay太多的代码-为什么不缩小问题的范围并发布显示问题的最小代码？好的，我不太确定为什么会出现错误，所以我发布了大部分错误part@ParagJain-学会调试-使人能够缩小调试范围little@EdHeal你如何调试一个没有编译的程序？当你编写
mm1时好了，你能推荐一些关于模板的好参考或教程吗？我需要在这里添加更多的函数，比如重载new和[]==for MemSet…..在这里有一个关于这个主题的很好的演练，所以：我不能使用向量，但谢谢你，这将帮助我理解。。。。
 ////Set and MemSet class

      template <class T>
     class Set
     {
            public :
                virtual bool find(T x) =0;
                virtual bool add(T x)  =0;
    };


template<class T>
class MemSet    : public Set<T> 
{
    public:
    T *array;
    int arraysize,currentsize;
template <class T1> 
friend  istream& operator >> (istream& s,MemSet<T1>& m );
template <class T1> 
friend ostream& operator << (ostream& s,MemSet<T1>& m );        

};


template <class T>
ostream& operator << (ostream& s,MemSet<T>& m )
{
    for(int i=0;i<m.getCurrentsize();i++)
    s << m.array[i];


    return s;
    }

////Record class
class Record
        {
            public:
            int age;
            std::string first_name,last_name;


friend  istream& operator >> (istream& s,Record& r );
friend ostream& operator << (ostream& s,Record& r );        
};

istream& operator >> (istream& s,Record& r )
                    {       
                        s>>r.age;
                        s>>r.first_name;
                        s>>r.last_name;
                        return s;
                        }               
ostream& operator << (ostream& out,Record& r )
                    {
                        out << r.age ;
                        out << r.first_name ;
                        out << r.last_name ;
                        return out ;
                        }

SetMain.cpp: In function ‘int main()’:
SetMain.cpp:36:6: error: no match for ‘operator<<’ in ‘mm1 << mset’
SetMain.cpp:36:6: note: candidates are:
Set.cpp:111:10: note: template<class T> std::ostream& operator<<(std::istream&, MemSet<T>&)
Record.cpp:46:10: note: std::ostream& operator<<(std::ostream&, Record&)
Record.cpp:46:10: note:   no known conversion for argument 1 from ‘MemSet<MemSet<Record> >’ to ‘std::ostream& {aka std::basic_ostream<char>&}’

template<typename T>
MemSet<T>& operator << (MemSet<T>& m, const T& v ) {
    m.add (v);
    return m;
}

template<typename T>
class MemSet: public Set {
public:
    MemSet& operator << (const T& v ) {
        add (v);
        return *this;
    }
};

#include <iostream>
#include <vector>
#include <string>
using namespace std;

class Record
{
    friend istream& operator>> (istream& s, Record& r);
    friend ostream& operator<< (ostream& s, Record& r);

public:
    int GetAge(void) const { return m_nAge; }
    const std::string& GetFirstName(void) const { return m_strFirstName; }
    const std::string& GetLastName(void) const { return m_strLastName; }

private:
    int m_nAge;
    string m_strFirstName;
    string m_strLastName;
};

istream& operator>> (istream& s, Record& r)
{
    s >> r.m_nAge;
    s >> r.m_strFirstName;
    s >> r.m_strLastName;
    return s;
}

ostream& operator<< (ostream& s, Record& r)
{
    s << "Individual: " << r.m_strLastName << ", "
        << r.m_strFirstName << " (" << r.m_nAge << " years)" << endl;
    return s;
}

template<class T>
class MemSet : public vector<T>
{
    template<class T1>
    friend ostream& operator<< (ostream& s, MemSet<T1>& m);

    template<class T1>
    friend MemSet<T1>& operator<< (MemSet<T1>& m, T1& t);
};

template<class T>
ostream& operator<< (ostream& s, MemSet<T>& m)
{
    for (typename vector<T>::iterator it = m.begin(); it != m.end(); ++it)
        s << *it;
    return s;
}

template<class T>
MemSet<T>& operator<< (MemSet<T>& m, T& t)
{
    m.push_back(t);
    return m;
}

int main(int argc, char** argv)
{
    MemSet<Record> mset1, mset2;
    MemSet< MemSet<Record> > mm;
    Record temp;

    cin >> temp; mset1.push_back(temp);
    cin >> temp; mset1.push_back(temp);
    cin >> temp; mset1.push_back(temp);

    cin >> temp; mset2.push_back(temp);
    cin >> temp; mset2.push_back(temp);
    cin >> temp; mset2.push_back(temp);

    cout << mset1 << endl;

    mm << mset1;
    mm << mset2;

    cout << mm << endl;

    return 0;
}