C++ 合并排序算法在一个条件下合并第三个数组中的两个数组

这是一种在一定条件下合并两个数组的算法。它首先比较两个数组的索引，如果arrayP1的索引等于arrayp2的索引，它会将该索引存储到应答数组中。 有人能帮我把这个算法翻译成c语言吗++

#include <iostream>
#include <cstdlib>
#include <conio.h>
using namespace std;

int main()
 { 

int sizeofarray=0,i=0 ,j=0, num=0, answers[]={};
cout<<"enter the size of array"<<endl;
cin>>sizeofarray;//take size of array from user
int array1[sizeofarray];
int array2[sizeofarray];
cout<<"please enter a sorted array member of Array1"<<endl;
//input of array element 
for ( i=0 ; i<=sizeofarray; i++)
{
cin>>array1[i];
}
system("CLS");
cout<<"please enter a sorted array member of Array2"<<endl;
for (j=0 ; j<=sizeofarray; j++)
{
cin>>array2[j];
}
 ***strong text***system("CLS");
//comparing the array element and storing the similar items to another         array
while(array1[i]!=NULL && array2[j]!=NULL){
if(array1[i]==array2[j]){
answer[num++]=array1[i];
i++;
j++;
}
else if(array1[i]<array2[j])
{
i++;
}else{
  j++;
   }
 i++;
 j++;
 }
 cout<<"The number of common elements"<<num<<endl;
 cout<<"These are the common numbers: ";
 for (int k=0;k<num;k++){
cout<<answer[k]<<" ";
 }
 getch();
 return 0;

 }

---

也许有人可以。我也这么认为，看起来没那么难。到目前为止你试过什么？包括不合并但与2个排序集相交的代码。您的标题有误导性，因为它不是合并两个数组的算法。这是一个求交的算法。请将您的问题显示出来。您应该至少包括一个大纲，但最好是一个有问题的代码的大纲，然后我们可以尝试帮助解决具体问题。你也应该阅读。

#include <iostream>
#include <cstdlib>
#include <conio.h>
using namespace std;

int main()
{

int sizeofarray=0,i=0 ,j=0, num=0, answers[]={};
cout<<"enter the size of array"<<endl;
cin>>sizeofarray;//take size of array from user
int array1[sizeofarray];
int array2[sizeofarray];
cout<<"please enter a sorted array member of Array1"<<endl;
//input of array element 
for ( i=0 ; i<=sizeofarray; i++)
{
    cin>>array1[i];
}
system("CLS");
cout<<"please enter a sorted array member of Array2"<<endl;
for (j=0 ; j<=sizeofarray; j++)
{
    cin>>array2[j];
}
system("CLS");
//comparing the array element and storing the similar items to another array
while(array1[i]!=NULL && array2[j]!=NULL){
    if(array1[i]==array2[j]){
    answer[num++]=array1[i];
    i++;
    j++;
    }
    else if(array1[i]<array2[j])
{
i++;
}else{
j++;
    }
i++;
j++;
}
cout<<"The number of common elements"<<num<<endl;
cout<<"These are the common numbers: ";
for (int k=0;k<num;k++){
    cout<<answer[k]<<" ";
}
getch();
return 0;

}