C++ c++；赋值在if语句中不起作用

您好，我正在使用两个数组为指定员工创建工资单。一个用于保存员工详细信息，另一个用于所需的计算。具有高级身份的员工与初级成员支付不同的税费和租金。我尝试在for循环中使用条件来使用条件分配不同的租金和税收值，但是下级（后者else if）超过了条件，并且条件不能正常工作。 这是我的密码

#include<iostream>
#include<string>
#include<iomanip>

using namespace std;
int main()
{

    cout<<"\t\t\t\t business application developers association \n";


cout<<" \t\t\t\t\t\t payroll for month ending\n \t\t\t\t\t\t\n\n";


cout<<"employee id\t"<<"name\t"<<"gender\t"<<"department\t"<<"date engaged\t"

<<"status\t"<<"annual gross\t"<<"monthly basic\t"<< "ssnit\t"<<"taxable 

income\t"<<"income tax\t"<< "transport\t rent\t"<<" total deduction\t"<< "take home \n";


    const int names=14;

    const int attributes=6;

string employee[names][attributes]={
    {"AB/1001","KOFI","MALE","SOFTWARE","31-AUG-10","SENIOR" },
    {"AB/1002","AMA","FEMALE","HARDWARE","31-AUG-10","SENIOR" },
    {"AB/1003","AKOS","FEMALE","HARDWARE","31-AUG-10","JUNIOR" },
    {"AB/1004","JAMES","MALE","HARDWARE","31-AUG-10","JUNIOR" },
    {"AB/1005","JONES","MALE","PRODUCTION","31-AUG-10","SENIOR" },
    {"AB/1006","BEAUTY","FEMALE","PRODUCTION","31-AUG-10","JUNIOR" },
    {"AB/1007","KWESI","MALE","HARDWARE","31-JUL-12","JUNIOR" },
    {"AB/1008","AFI","FEMALE","SOFTWARE","31-JUL-12","JUNIOR" },
    {"AB/1009","ROGER","MALE","SOFTWARE","31-JUL-12","SENIOR" },
    {"AB/1010","WISDOM","MALE","HARDWARE","31-JUL-12","JUNIOR" },
    {"AB/1011","HOPE","MALE","PRODUCTION","31-JUL-12","JUNIOR" },
    {"AB/1012","MAGGI","FEMALE","PRODUCTION","31-JUL-12","JUNIOR" },
    {"AB/1013","FRED","MALE","HARDWARE","31-JUL-12","SENIOR" },
    {"AB/1014","PAT","FEMALE","HARDWARE","31-JUL-12","JUNIOR" },



}
;//end of array initialisation for employees


double wages[11];

for(int a=0;a<=13;a++){

    if(employee[a][5]=="SENIOR"){
        wages[0]=120000;//annual salary
        wages[1]=0.15;//income tax rate
        wages[2]=600;//transport allowance
        wages[3]=300; //rent

    }//end of if
    else if(employee[a][5]=="JUNIOR"){
            wages[0]=40000;//annual salary
        wages[1]=0.10;//income tax rate
        wages[2]=300;//transport allowance
        wages[3]=150; //rent

    }//end of else
wages[4]=wages[0]/12;//monthly basic
wages[5]=wages[4]*0.05;//ssnit employee
wages[6]=wages[4]*0.125;//ssnit employer
wages[7]=wages[4]-wages[6];//taxable income
wages[8]=wages[7]*wages[1];//income tax
wages[9]=wages[5]+wages[8];//total deduction
wages[10]=wages[2]+wages[3];//total allowance
wages[11]=wages[4]+wages[10]-wages[9];//take home
 //ready for printing.
}//end of major for loop
 for (int m=0;m<=13;m++){
 for(int n=0;n<=5;n++){
 cout<<employee[m][n]<<"\t";


 }
 for(int b=0;b<=10;b++){
    cout <<wages[b]<<"\t";
}
    cout<<endl;

}//end of printing for loop


    return 0;
}

#包括
#包括
#包括
使用名称空间std；
int main（）
{
cout问题在于您只有一个数组，
工资
，用于存储所有员工的信息。因此，当您打印
工资
时，您只打印与最后一名员工对应的工资信息

您可以使用以下方法之一解决此问题

计算完工资后，立即在employee循环中打印工资
使用二维数组存储工资，然后像现在一样在末尾打印工资
解决方案1

计算工资并在一个循环中打印

for(int a=0;a<=13;a++){

  if(employee[a][5]=="SENIOR"){
     wages[0]=120000;//annual salary
     wages[1]=0.15;//income tax rate
     wages[2]=600;//transport allowance
     wages[3]=300; //rent

  }//end of if
  else if(employee[a][5]=="JUNIOR"){
     wages[0]=40000;//annual salary
     wages[1]=0.10;//income tax rate
     wages[2]=300;//transport allowance
     wages[3]=150; //rent

  }//end of else
  wages[4]=wages[0]/12;//monthly basic
  wages[5]=wages[4]*0.05;//ssnit employee
  wages[6]=wages[4]*0.125;//ssnit employer
  wages[7]=wages[4]-wages[6];//taxable income
  wages[8]=wages[7]*wages[1];//income tax
  wages[9]=wages[5]+wages[8];//total deduction
  wages[10]=wages[2]+wages[3];//total allowance
  wages[11]=wages[4]+wages[10]-wages[9];//take home
  //ready for printing.

  for(int n=0;n<=5;n++){
     cout<<employee[a][n]<<"\t";
  }
  for(int b=0;b<=10;b++){
     cout <<wages[b]<<"\t";
  }
  cout<<endl;
}//end of major for loop

for（inta=0；a您的数据应该这样表示

struct Wages
{
   double Salary;
   double TaxRate;
   double TransportAllowance;
  // etc
}

那就有

std::vector<Wages> EmployeeWages();

对员工也一样
你到底面临什么问题？我的if条件不起作用。我想使用if条件计算不同的税率和老年人和老年人的租金津贴。但它只给我老年人和老年人的税率和租金津贴。你能详细说明一下吗？另外，这是一种可怕的存储数据的方法工资[0]=工资，工资[1]=tax，…您应该创建一个结构并存储在vector@pglinnaeus，我同意pm100。而且，
numberOfEmployees
将比
name
更好。
std::vector<Wages> EmployeeWages();

Wages w = new Wages();
 if(employee[a][5]=="SENIOR"){
     w.Salary=120000;//annual salary
     w.Tax=0.15;//income tax rate
     w.TransportAllowance=600;//transport allowance
  }
  // etc
EmployeeWages.push_back(w);