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C++ C++;:如何返回模板类中定义的别名?_C++_Templates_Alias - Fatal编程技术网

C++ C++;:如何返回模板类中定义的别名?

C++ C++;:如何返回模板类中定义的别名?,c++,templates,alias,C++,Templates,Alias,所以我得到了模板类(缩写),如: 模板 类哈希映射{ 公众: 使用dataT=pair; 使用maybeT=可选; maybeT notFound=可选(); maybeT find(keyT&v); }; 当我试图定义find()时,我 模板 hashMap::maybeT hashMap::find(keyT&k) { 无法识别hashMap::maybeT(“应为类或命名空间”)。使用keyT和valueT限定hashMap也没有帮助 如何导出这些别名(或typedef,如果有办法的话

所以我得到了模板类(缩写),如:

模板
类哈希映射{
公众:
使用dataT=pair;
使用maybeT=可选;
maybeT notFound=可选();
maybeT find(keyT&v);
};
当我试图定义find()时,我

模板
hashMap::maybeT hashMap::find(keyT&k)
{
无法识别hashMap::maybeT(“应为类或命名空间”)。使用keyT和valueT限定hashMap也没有帮助


如何导出这些别名(或typedef,如果有办法的话)。

您需要消除依赖名称的歧义:

template <typename keyT, typename valueT>
typename hashMap<keyT, valueT>::maybeT hashMap<keyT,valueT>::find(keyT &k)
// ^^^^^
{
    // ...
}
模板
typename hashMap::maybeT hashMap::find(keyT&k)
// ^^^^^
{
// ...
}

(既然您正在编写模板,那么最好将所有内容都内联,并减少代码噪音。否则,您应该将
inline
添加到成员函数声明中。)

啊!谢谢。我尝试了错误的消歧方法:typename hashMap::maybeT
template <typename keyT, typename valueT>
hashMap::maybeT hashMap<keyT,valueT>::find(keyT &k)
{
template <typename keyT, typename valueT>
typename hashMap<keyT, valueT>::maybeT hashMap<keyT,valueT>::find(keyT &k)
// ^^^^^
{
    // ...
}