C++ 为梯度计算中提供的单个图像并排生成4个图像的输出
下面的代码用于计算图像所有像素处的归一化梯度。但在计算梯度时使用imshow,而不是显示所提供图像的梯度,而是将所提供图像的梯度并排显示4次C++ 为梯度计算中提供的单个图像并排生成4个图像的输出,c++,opencv,image-processing,C++,Opencv,Image Processing,下面的代码用于计算图像所有像素处的归一化梯度。但在计算梯度时使用imshow,而不是显示所提供图像的梯度,而是将所提供图像的梯度并排显示4次 #include "opencv2/imgproc/imgproc.hpp" #include "opencv2/highgui/highgui.hpp" #include <opencv2/core/core.hpp> #include<iostream> #include<math.h> using namespac
#include "opencv2/imgproc/imgproc.hpp"
#include "opencv2/highgui/highgui.hpp"
#include <opencv2/core/core.hpp>
#include<iostream>
#include<math.h>
using namespace cv;
using namespace std;
Mat mat2gray(const Mat& src)
{
Mat dst;
normalize(src, dst, 0.0, 1.0, NORM_MINMAX);
return dst;
}
Mat setImage(Mat srcImage){
//GaussianBlur(srcImage,srcImage,Size(3,3),0.5,0.5);
Mat avgImage = Mat::zeros(srcImage.rows,srcImage.cols,CV_32F);
Mat gradient = Mat::zeros(srcImage.rows,srcImage.cols,CV_32F);
Mat norMagnitude = Mat::zeros(srcImage.rows,srcImage.cols,CV_32F);
Mat orientation = Mat::zeros(srcImage.rows,srcImage.cols,CV_32F);
//Mat_<uchar> srcImagetemp = srcImage;
float dx,dy;
for(int i=0;i<srcImage.rows-1;i++){
for(int j=0;j<srcImage.cols-1;j++){
dx=srcImage.at<float>(i,j+1)-srcImage.at<float>(i,j);
dy=srcImage.at<float>(i+1,j)-srcImage.at<float>(i,j);
gradient.at<float>(i,j)=sqrt(dx*dx+dy*dy);
orientation.at<float>(i,j)=atan2(dy,dx);
//cout<<gradient.at<float>(i,j)<<endl;
}
}
GaussianBlur(gradient,avgImage,Size(7,7),3,3);
for(int i=0;i<srcImage.rows;i++){
for(int j=0;j<srcImage.cols;j++){
norMagnitude.at<float>(i,j)=gradient.at<float>(i,j)/max(avgImage.at<float>(i,j),float(4));
//cout<<norMagnitude.at<float>(i,j)<<endl;
}
}
imshow("b",(gradient));
waitKey();
return norMagnitude;
}
int main(int argc,char **argv){
Mat image=imread(argv[1]);
cvtColor( image,image, CV_BGR2GRAY );
Mat newImage=setImage(image);
imshow("a",(newImage));
waitKey();
}
您传入的源图像的类型为CV_8UC1,但您将其读取为浮点数:
dx=srcImage.at<float>(i,j+1)-srcImage.at<float>(i,j);
dy=srcImage.at<float>(i+1,j)-srcImage.at<float>(i,j);
dx=(float)(srcImage.at<unsigned char>(i,j+1)-srcImage.at<unsigned char>(i,j));
dy=(float)(srcImage.at<unsigned char>(i+1,j)-srcImage.at<unsigned char>(i,j));