C++ 如何允许用户指定名称，程序将使用该名称报告结果？

该程序将统计来自四个县总计和每个县的两名候选人的选票，并显示获胜者。用户必须输入每个县和候选人的投票。现在，感谢你们，我为上述目的解决了这些问题。但是现在，我想添加Cout语句，允许用户指定四个县和两个候选人的名字。以及使用名称来报告结果

我不知道如何在循环中加入变量，以便在报告结果（如总冠军和每个县的冠军）时打印姓名

谢谢你的时间

#include<iostream>
using namespace std;
int tier1();
int main(void)
{
 int return_val = tier1();
 if (return_val < 0) // print an error
 return 0;
}
int tier1(){
 int votes[8];
 int i, j, N; // variables
 int k = 0;
 for (i=0; i<4; i++)
 {
  cout << "county" << i << "\n"; // lists the 4 counties/candidates
  for (j=0; j<2; j++)
{
      cout << "How many votes did the candidate " << j << " get?\n";
      N=0;
       cin >> N;
      votes[k++] = N;;
   }
   if (votes[k-2] + votes[k-1] > 100) //checking if it goes over 100 votes
   {
    cout << "One of the counties has too many votes. Exiting!\n"; // Print an error
    exit(1);
   }

 }

 int candidateOneVotes = 0; //resetting 
 int candidateTwoVotes = 0;
 for (i = 0; i < 8; i = i+2)
 {
 cout << votes[i] << "\n";
 cout << votes[i+1] << "\n";
 candidateOneVotes += votes[i];
 candidateTwoVotes += votes[i+1];
 }
 if (candidateOneVotes > candidateTwoVotes){
 cout << "The winner of the election is " << c0 << "\n";
 }
 else
 {
 cout << "The winner of the election is " << c1 << "\n";
 }
 cout << "Here is the voting results:\n";
 cout << c0 << " got ";
 cout << candidateOneVotes;
 cout << " votes\n ";
 cout << c1 << "got ";
 cout << candidateTwoVotes;
 cout << " votes ";

 return 0;

}

#包括
使用名称空间std；
int-tier1（）；
内部主（空）
{
int return_val=tier1（）；
if（return_val<0）//打印错误
返回0；
}
int第1层（）{
整数票[8]；
int i，j，N；//变量
int k=0；
对于（i=0；i，首先您需要拉入字符串和向量头的内容

#include <string>
#include <vector>

现在，您需要更新
main
以从
cin
读取候选人和县名称，并将这些名称传递给
tier1
函数

int main()
{
    cout << "Welcome to the VoteTime Program. Please do what it tells you.\n";

    std::string c0;
    cout << "Please name the candidate 0. (For example: Bob)\n";
    std::getline(cin, c0);

    std::string c1;
    cout << "Please name the candidate 1. (For example: John)\n";
    std::getline(cin, c1);

    std::vector<std::string> counties;
    for (int i = 0; i < 4; ++i)
    {
        std::string county;
        cout << "Please name county #" << i << '\n';
        std::getline(cin, county);
        counties.push_back(county);
    }


    int return_val = tier1(c0, c1, counties);

    if (return_val < 0) // print an error
        return 0;
}

你知道这段代码不会编译，对吗？是的，它编译和运行时没有顶部的cout语句。我只是添加了那些cout语句作为一个想法，我知道它不完整，现在不会编译，如果你想看到程序编译和运行。我可以删除cout语句和int c0，c1，…。然后它应该运行。我继续进行编辑我刚才为一个想法添加的部分。基本上，现在，程序应该编译并在
main
中运行，注释是不存在的。您不会打印错误消息。相反，
return
语句绑定到
if
语句并有条件地执行。哇，这肯定很有用！但我需要用户还要指定县的名称吗？更新了答案以包括对县的支持。如果您不能使用
std:：vector
，请切换到使用裸数组并揍您的讲师。我非常感谢您的帮助。但是，在“您忘记了
”include之前，我遇到了一系列错误，例如预期的不合格id。：/code>：有一件事我没有注意到在用户为候选人添加姓名之后是帽子。它询问“候选人0获得了多少选票”，而不是说出用户添加的姓名？我不知道如何处理这个问题。最后，它确实说出了用户添加的姓名。只是不是在询问时。但对于县，它工作得非常好
int main()
{
    cout << "Welcome to the VoteTime Program. Please do what it tells you.\n";

    std::string c0;
    cout << "Please name the candidate 0. (For example: Bob)\n";
    std::getline(cin, c0);

    std::string c1;
    cout << "Please name the candidate 1. (For example: John)\n";
    std::getline(cin, c1);

    std::vector<std::string> counties;
    for (int i = 0; i < 4; ++i)
    {
        std::string county;
        cout << "Please name county #" << i << '\n';
        std::getline(cin, county);
        counties.push_back(county);
    }


    int return_val = tier1(c0, c1, counties);

    if (return_val < 0) // print an error
        return 0;
}

int tier1(
    const std::string& c0,
    const std::string& c1,
    const std::vector<std::string>& counties)
{
    int votes[8];
    int i, j, N; // variables
    int k = 0;
    for (i = 0; i < counties.size(); i++)
    {
        cout << "county " << counties[i] << "\n";
        for (j = 0; j<2; j++)
        {
            cout << "How many votes did the candidate " << j << " get?\n";
            N = 0;
            cin >> N;
            votes[k++] = N;;
        }
        //checking if it goes over 100 votes
        if (votes[k - 2] + votes[k - 1] > 100)
        {
            cout << "One of the counties has too many votes. Exiting!\n";
            exit(1);
        }

    }

    int candidateOneVotes = 0; //resetting 
    int candidateTwoVotes = 0;
    for (i = 0; i < 8; i = i + 2)
    {
        cout << votes[i] << "\n";
        cout << votes[i + 1] << "\n";
        candidateOneVotes += votes[i];
        candidateTwoVotes += votes[i + 1];
    }
    if (candidateOneVotes > candidateTwoVotes){
        cout << "The winner of the election is " << c0 << "\n";
    }
    else
    {
        cout << "The winner of the election is " << c1 << "\n";
    }
    cout << "Here is the voting results:\n";
    cout << c0 << " got ";
    cout << candidateOneVotes;
    cout << " votes\n ";
    cout << c1 << "got ";
    cout << candidateTwoVotes;
    cout << " votes ";

    return 0;
}