C++只接受正整数
我目前正在进行一项编程作业,在检查用户输入时遇到问题。该程序只输入两个正数,但当我输入一个字符(例如“a”)作为第一个数字时,程序会接受它并输出它,就像我输入了零一样。它应该输出无效的数字:数字必须是正整数。有人能告诉我我做错了什么吗?谢谢大家!C++只接受正整数,c++,C++,我目前正在进行一项编程作业,在检查用户输入时遇到问题。该程序只输入两个正数,但当我输入一个字符(例如“a”)作为第一个数字时,程序会接受它并输出它,就像我输入了零一样。它应该输出无效的数字:数字必须是正整数。有人能告诉我我做错了什么吗?谢谢大家! //Program where user enters two positive numbers //and program will display various things. #include <iostream> using n
//Program where user enters two positive numbers
//and program will display various things.
#include <iostream>
using namespace std;
int main()
{
//Displays information of what program will do
cout<< "Practice with iterations\n\n"
<< "The function of this program is, given 2 positive numbers, the"
<< " program";
cout<< "\nwill display the following\n\n";
cout<< "\t1. All even numbers between firstNum and secondNum.\n"
<< "\t2. All odd numbers between firstNum and secondNum.\n"
<< "\t3. Sum of all even numbers between firstNum and secondNum.\n"
<< "\t4. Sum of all odd numbers between firstNum and secondNum.\n"
<< "\t5. All prime numbers between firstNum and secondNum.\n"
<< "\t6. Factorial of the secondNum.\n"
<< "\t7. The numbers and their squares between firstNum and "
<< "secondNum."<< endl;
//Declare first and second number variables
int firstNum;
int secondNum;
bool flag= true; //Set to true
char x; //Use to see if value entered is letter
//Ask user to input values
cout<< "\n\nEnter the first number:\t\t";
cin>> firstNum;
if (cin.fail())
{
cin.clear();
cin.ignore(256,'\n');
flag= 0;
}
cout<< "Enter the second number:\t";
cin>> secondNum;
if (cin.fail())
{
cin.clear();
cin.ignore(256,'\n');
flag= 0;
}
//If user puts wrong input
if (firstNum>secondNum)
cout<< "\nError: First number must be < second number.\n";
else if (firstNum<0 || secondNum<0)
cout<< "\nError: Invalid number: Number must be positive.\n";
else if (firstNum==x || secondNum==x)
cout<< "\nError: Invalid number: Numbers must be positive integer.\n";
else
{
cout<< "\nYou entered: "<< firstNum<< " and "<< secondNum;
}
return 0;
}
这个测试是错误的,x没有初始化,它没有真正的意义。另外,你已经使用了这个标志来测试失败输入的情况,我假设你的代码应该是这样的
#include <iostream>
using namespace std;
int main()
{
//Displays information of what program will do
cout << "Practice with iterations\n\n"
<< "The function of this program is, given 2 positive numbers, the"
<< " program";
cout << "\nwill display the following\n\n";
cout << "\t1. All even numbers between firstNum and secondNum.\n"
<< "\t2. All odd numbers between firstNum and secondNum.\n"
<< "\t3. Sum of all even numbers between firstNum and secondNum.\n"
<< "\t4. Sum of all odd numbers between firstNum and secondNum.\n"
<< "\t5. All prime numbers between firstNum and secondNum.\n"
<< "\t6. Factorial of the secondNum.\n"
<< "\t7. The numbers and their squares between firstNum and "
<< "secondNum." << endl;
//Declare first and second number variables
int firstNum;
int secondNum;
bool flag = true; //Set to true
//Ask user to input values
cout << "\n\nEnter the first number:\t\t";
cin >> firstNum;
if (cin.fail())
{
cin.clear();
cin.ignore(256, '\n');
flag = 0;
}
cout << "Enter the second number:\t";
cin >> secondNum;
if (cin.fail())
{
cout << "lol" << endl;
cin.clear();
cin.ignore(256, '\n');
flag = 0;
}
if (flag) {
if (firstNum > secondNum)
cout << "\nError: First number must be < second number.\n";
else if (firstNum < 0 || secondNum < 0)
cout << "\nError: Invalid number: Number must be positive.\n";
else
{
cout << "\nYou entered: " << firstNum << " and " << secondNum;
}
}
else cout << "Error input" << endl;
return 0;
}
如果在读取输入时出错,那么您已经正确地解释了第一步-清除输入流并清除cin的错误状态。您缺少的是在变量中读取有效的内容。为此,您需要一个循环
while (true )
{
//Ask user to input values
cout<< "\n\nEnter the first number:\t\t";
// Try to read the input. If it is successful, break out of the loop.
if ( cin>> firstNum )
{
break;
}
// Clear the error flag. Clear the input stream. Try again.
cin.clear();
cin.ignore(256,'\n');
}
对第二个数字执行相同的操作
while (true )
{
//Ask user to input values
cout<< "\n\nEnter the first number:\t\t";
// Try to read the input. If it is successful, break out of the loop.
if ( cin>> firstNum )
{
break;
}
// Clear the error flag. Clear the input stream. Try again.
cin.clear();
cin.ignore(256,'\n');
}