C++ strftime在I';我想展示一下
嘿,伙计们,我想知道是否有人能向我指出这一点。我目前正试图在cmd提示符的右角显示日期和时间,但我得到了额外的字符,然后我要求的。这就是我目前所拥有的C++ strftime在I';我想展示一下,c++,strftime,C++,Strftime,嘿,伙计们,我想知道是否有人能向我指出这一点。我目前正试图在cmd提示符的右角显示日期和时间,但我得到了额外的字符,然后我要求的。这就是我目前所拥有的 time_t rawtime; struct tm * timeinfo; char buffer[80]; time(&rawtime); timeinfo = localtime(&rawtime); // this displays "23 Date:etcetcetc" cout
time_t rawtime;
struct tm * timeinfo;
char buffer[80];
time(&rawtime);
timeinfo = localtime(&rawtime);
// this displays "23 Date:etcetcetc"
cout << "\n\n\n\n\n\n\n\n\n\n\n\n";
cout << strftime(buffer, 80, "\t\t\t\t\t\t\tDate: %d/%m/%Y", timeinfo);
puts(buffer);
// and this displays "16Time:etcetcetc"
cout << "\t\t\t\t\t\t\t";
cout << strftime(buffer, 80,"Time: %I:%M:%S \n", timeinfo);;
puts(buffer);
time\u t rawtime;
结构tm*时间信息;
字符缓冲区[80];
时间(&rawtime);
timeinfo=localtime(&rawtime);
//显示“23日期:等”
coutcout尝试替换此:
cout << strftime(buffer, 80, "\t\t\t\t\t\t\tDate: %d/%m/%Y", timeinfo);
谢谢,伙计们请客真不敢相信事情这么简单!
cout << strftime(buffer, 80,"Time: %I:%M:%S \n", timeinfo);
cout << strftime(buffer, 80, "\t\t\t\t\t\t\tDate: %d/%m/%Y", timeinfo);
strftime(buffer, 80, "\t\t\t\t\t\t\tDate: %d/%m/%Y", timeinfo);