C++ 编写一个程序，使用枚举类型c+销售爆米花和饮料+；班

我的任务是：编写一个使用枚举类型销售爆米花和饮料的程序。您必须在您的应用程序中使用以下内容： 节目： 枚举大小{小、中、大、巨型}； 大小爆米花大小，饮用； 您应该创建一个菜单，要求用户选择他们想要的饮料的大小，并选择饮料的大小 他们想要爆米花。然后你应该打印出饮料和爆米花的总成本

价格： 小爆米花=1.25，中爆米花=2.25，大爆米花=3.50，特大爆米花=4.25 小苏打=1.50，中苏打=2.50，大苏打=3.75，大苏打=4.50

这是我的密码：

int main()
{
    enum sizes { SMALL, MEDIUM, LARGE, JUMBO };
    sizes popcornSize, drinkSize;

    double sp=1.25, mp=2.25, lp=3.50, jp=4.25, TOTALp, TOTALs, ss=1.50,         ms=2.50, ls=3.75, js=4.50 ;
    char choice, answer, Psize, Ssize;
    int how_many;
    cout << "Hello I am selling popcorn and sodas, would you like to buy  some? type yes or no please." << endl;
    cin >> choice;
    if (choice == 'yes')
    {
        cout << "Great, what would you like popcorn or soda? Type P for popcorn and S for soda." << endl;
        cin >> answer;
        if (answer = 'P')
        {
            cout << "what size popcorn would you like (type s for small, m for medium, l for large or j for jumbo) and how many (type a single number)?" << endl;
            cin >> Psize >> how_many;
            if (Psize = 's')
            {
                TOTALp = sp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }
            else if (Psize = 'm')
            {
                TOTALp = mp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }
            else if (Psize = 'l')
            {
                TOTALp = lp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }
            else if (Psize = 'j')
            {
                TOTALp = jp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }


            else if (answer = 'S')
            {

                cout << "what size soda would you like (type small, medium, large or jumbo) and how many (type a single number)?" << endl;
                cin >> Ssize >> how_many;
                if (Ssize = 's')
                {
                    TOTALs = ss*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }
                else if (Ssize = 'm')
                {
                    TOTALs = ms*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }
                else if (Ssize = 'l')
                {
                    TOTALs = ls*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }
                else if (Ssize = 'j')
                {
                    TOTALs = js*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }

            }
            cout << "Thanks for buying come again soon." << endl;
        }

        }
        else if (choice == 'no')
            cout << "Okay have a great day!" << endl;
    return 0;
}

intmain（）
{
枚举大小{小、中、大、巨型}；
大小爆米花大小，饮用；
双sp=1.25，mp=2.25，lp=3.50，jp=4.25，TOTALp，TOTALs，ss=1.50，ms=2.50，ls=3.75，js=4.50；
字符选择，回答，心灵感应，心灵感应；
int多少；
不能选择；
如果（选项==“是”）
{
答不上来；
如果（答案='P'）
{
想一想>>有多少人；
如果（Psize='s'）
{
TOTALp=sp*多少；
不能程序结束，因为选项从来不是“是”或“否”。因为选项是字符，所以它只能是单个字符。将“是”更改为“y”，将“否”更改为“n”，它应该可以工作

我给出了一个如何编写switch语句的示例，以便在代码的其余部分对其进行调整

#include "stdio.h"
#include "iostream"

using namespace std;

int main()
{
    enum sizes { SMALL, MEDIUM, LARGE, JUMBO };
    sizes popcornSize, drinkSize;

    double sp=1.25, mp=2.25, lp=3.50, jp=4.25, TOTALp, TOTALs, ss=1.50,         ms=2.50, ls=3.75, js=4.50 ;
    char choice, answer, Psize, Ssize;
    int how_many;
    cout << "Hello I am selling popcorn and sodas, would you like to buy  some? type yes or no please." << endl;
    cin >> choice;
    switch(choice)
    {
    case 'y':
        cout << "Great, what would you like popcorn or soda? Type P for popcorn and S for soda." << endl;
        cin >> answer;
        if (answer = 'P')
        {
            cout << "what size popcorn would you like (type s for small, m for medium, l for large or j for jumbo) and how many (type a single number)?" << endl;
            cin >> Psize >> how_many;
            if (Psize = 's')
            {
                TOTALp = sp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }
            else if (Psize = 'm')
            {
                TOTALp = mp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }
            else if (Psize = 'l')
            {
                TOTALp = lp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }
            else if (Psize = 'j')
            {
                TOTALp = jp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }


            else if (answer = 'S')
            {

                cout << "what size soda would you like (type small, medium, large or jumbo) and how many (type a single number)?" << endl;
                cin >> Ssize >> how_many;
                if (Ssize = 's')
                {
                    TOTALs = ss*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }
                else if (Ssize = 'm')
                {
                    TOTALs = ms*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }
                else if (Ssize = 'l')
                {
                    TOTALs = ls*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }
                else if (Ssize = 'j')
                {
                    TOTALs = js*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }

            }
            cout << "Thanks for buying come again soon." << endl;
        }
    break;
    case 'n':
        cout << "Okay have a great day!" << endl;
    break;
    default:
        cout << "I dont understand...!" << endl;
    break;
    }
    return 0;
}

#包括“stdio.h”
#包括“iostream”
使用名称空间std；
int main（）
{
枚举大小{小、中、大、巨型}；
大小爆米花大小，饮用；
双sp=1.25，mp=2.25，lp=3.50，jp=4.25，TOTALp，TOTALs，ss=1.50，ms=2.50，ls=3.75，js=4.50；
字符选择，回答，心灵感应，心灵感应；
int多少；
不能选择；
开关（选择）
{
案例“y”：
答不上来；
如果（答案='P'）
{
想一想>>有多少人；
如果（Psize='s'）
{
TOTALp=sp*多少；
非常感谢！但是，关于爆米花和汽水的大小和价格，我仍然在思考如何在代码中实现枚举数据。问题是，您希望用户输入什么？例如，您可以编写一个switch case语句，接受用户输入并设置每种情况下的枚举值。