C++ Qt:从QTableWidget中的按钮获取文本
我的Qt应用程序中有QTableWidget,我向其中添加了如下按钮:C++ Qt:从QTableWidget中的按钮获取文本,c++,qt,qtablewidget,qpushbutton,C++,Qt,Qtablewidget,Qpushbutton,我的Qt应用程序中有QTableWidget,我向其中添加了如下按钮: QPushButton *startButton = new QPushButton("start"); ui->tableWidget_tvConnection->setCellWidget(row, col, startButton); connect(startButton, SIGNAL(clicked()), this, SLOT(startButtonPressed())); 当它被按下时,我需要从
QPushButton *startButton = new QPushButton("start");
ui->tableWidget_tvConnection->setCellWidget(row, col, startButton);
connect(startButton, SIGNAL(clicked()), this, SLOT(startButtonPressed()));
当它被按下时,我需要从中获取文本,所以我尝试了以下方法:
void MainWindow::startButtonPressed()
{
...
QPushButton *button = ui->tableWidget_tvConnection->cellWidget(row, col);
qDebug() << button->text();
}
那么,甚至可以从QTableWidget中的按钮获取文本吗?
如果不是,我有另一种方法在我的应用程序中处理这个问题,但这将非常好。您将获得
QWidget
,因此您应该将它转换为QPushButton
。之后,您可以将此按钮用作正常的按钮
。试试这个:
QPushButton *button = qobject_cast<QPushButton *>(ui->tableWidget_tvConnection->cellWidget(row, col));
if(button) {
//success
} else {
//bad
}
QPushButton*button=qobject\u cast(ui->tableWidget\u tvConnection->cellWidget(行、列));
如果(按钮){
//成功
}否则{
//坏的
}
СПааааа,чааа:)
QPushButton *button = qobject_cast<QPushButton *>(ui->tableWidget_tvConnection->cellWidget(row, col));
if(button) {
//success
} else {
//bad
}